Home > Database > Mysql Tutorial > mysql 生成日期维表

mysql 生成日期维表

WBOY
Release: 2016-06-07 14:51:07
Original
2322 people have browsed it

第一步,创建函数f_dim_day create procedure f_dim_day(in start_date VARCHAR(20),in date_count int) begin declare i int; set i=0; DELETE from dim_day; while idate_count do INSERT into dim_day (DAY_ID,DAY_SHORT_DESC,DAY_LONG_DESC,WEEK_ID,WEEK

第一步,创建函数 f_dim_day


create procedure f_dim_day(in start_date VARCHAR(20),in date_count int)
      begin
      declare i int;
      set i=0;
 DELETE from dim_day;
      while i
          INSERT into dim_day
(DAY_ID,DAY_SHORT_DESC,DAY_LONG_DESC,WEEK_ID,WEEK_LONG_DESC,MONTH_ID,MONTH_SHORT_DESC,MONTH_LONG_DESC,QUARTER_ID,QUARTER_LONG_DESC,YEAR_ID,YEAR_LONG_DESC)
SELECT 
REPLACE(start_date,'-','') DAY_ID,
DATE_FORMAT(STR_TO_DATE(start_date,'%Y-%m-%d %H:%i:%s'),'%Y-%m-%d') DAY_SHORT_DESC,
DATE_FORMAT(STR_TO_DATE(start_date,'%Y-%m-%d %H:%i:%s'),'%Y年%m月%d日') DAY_LONG_DESC,
DATE_FORMAT(STR_TO_DATE(start_date,'%Y-%m-%d %H:%i:%s'),'%Y%u') WEEK_ID,
DATE_FORMAT(STR_TO_DATE(start_date,'%Y-%m-%d %H:%i:%s'),'%Y年第%u周') WEEK_LONG_DESC,
DATE_FORMAT(STR_TO_DATE(start_date,'%Y-%m-%d %H:%i:%s'),'%Y%m') MONTH_ID,
DATE_FORMAT(STR_TO_DATE(start_date,'%Y-%m-%d %H:%i:%s'),'%Y-%m') MONTH_SHORT_DESC,
DATE_FORMAT(STR_TO_DATE(start_date,'%Y-%m-%d %H:%i:%s'),'%Y年第%m月') MONTH_LONG_DESC,
CONCAT(DATE_FORMAT(STR_TO_DATE(start_date,'%Y-%m-%d %H:%i:%s'),'%Y'),quarter(STR_TO_DATE( start_date,'%Y-%m-%d %H:%i:%s'))) QUARTER_ID,
CONCAT(DATE_FORMAT(STR_TO_DATE(start_date,'%Y-%m-%d %H:%i:%s'),'%Y'),'年第',quarter(STR_TO_DATE(start_date,'%Y-%m-%d %H:%i:%s')),'季度') QUARTER_LONG_DESC,
DATE_FORMAT(STR_TO_DATE(start_date,'%Y-%m-%d %H:%i:%s'),'%Y') YEAR_ID,
DATE_FORMAT(STR_TO_DATE(start_date,'%Y-%m-%d %H:%i:%s'),'%Y年') YEAR_LONG_DESC
from dual;
          set i=i+1;
set start_date = DATE_FORMAT(date_add(STR_TO_DATE(start_date,'%Y-%m-%d %H:%i:%s'),interval 1 day),'%Y-%m-%d');
end while;

end;

第二步,调用函数传入开始时间和天数 ,执行如下sql:

call f_dim_day(‘2015-01-01’,365) 


生成效果如下:



Related labels:
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template