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Oracle的Flashback用法汇总

Jun 07, 2016 pm 03:03 PM
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欢迎进入Oracle社区论坛,与200万技术人员互动交流 >>进入 ? 6.进行数据恢复 ? 禁止表上的触发器 alter trigger sphsy.T_INS_LOGIN_TABLE disable ; ? 恢复数据 insert into sphsy.login_table select * from sphsy.login_table as of timestamp to_timestam

欢迎进入Oracle社区论坛,与200万技术人员互动交流 >>进入

    ? 6.进行数据恢复

    ? 禁止表上的触发器

    alter trigger sphsy.T_INS_LOGIN_TABLE disable ;

    ? 恢复数据

    insert into sphsy.login_table

    select * from sphsy.login_table

    as of timestamp to_timestamp(’2012-04-17 17:20:30′,’YYYY-MM-DD HH24:MI:SS’)

    where id > 201204171078

    and id

    ? 恢复触发器

    alter trigger sphsy.T_INS_LOGIN_TABLE enable ;

    ? 7.晚于区间的数据回来了3130 = 3016 +62 + 后来的数据。实现了区间恢复误删除。

    select program,count(*)

    from sphsy.login_table a

    where a.id >= 201204171078

    group by program ;

    ? D. flashback table 恢复表到先前状态

    /*

    flashback查询可以用于恢复被误删除的表行数据,但是用户在表上执行了其他的DML语句误操作(insert或update),则不能直接使用flashback查询将表数据恢复到先前时间点,从oracle10g开始,使用flashback table语句可以将表恢复到先前时间点,通过使用该特征,可以避免执行基于时间点的不完全恢复,注意如果要在某个表上使用flashback table特征,则要求必须具有以下条件:

    a.用户必须具有flashback any table系统权限或flashback对象权限

    b.用户必修在表上具有select insert delete和alter权限

    c.必须合理设置初始化参数undo_retention,以确保UNDO信息保留足够时间

    d.必须激活行移动特征:alter table table_name enable row movement;

    */

    ? 1.查原始记录 ,区间内有62 行

    select *

    from sphsy.login_table a

    where a.id > 201204171078

    and a.id

    order by a.id ;

    ? 2.晚于区间的有 3074

    select count(*)

    from sphsy.login_table a

    where a.id >= 201204171141;

    ?3. 删除 ,先记下时间点,2012-04-17 17:43:46

    select to_char(sysdate,’YYYY-MM-DD HH24:MI:SS’) from dual ;

    delete from sphsy.login_table a

    where a.id > 201204171078

    and a.id

    ? 4.删除之后表 sphysy.login_table继续有修改 ,行3082

    select count(*)

    from sphsy.login_table a

    where a.id >= 201204171141;

    ?5.激活行移动特征

    alter table sphsy.login_table enable row movement

    ?6.利用闪回特性,直接恢复到删除时间点前

    flashback table sphsy.login_table to timestamp to_timestamp(’2012-04-17 17:43:46′,’YYYY-MM-DD HH24:MI:SS’);

    ? 7.晚于区间的数据 回到了3080 ,说明时间点之后的修改丢失。

    select count(*)

    from sphsy.login_table a

    where a.id >= 201204171141

    ? 8.往前推1分,恢复到删除之前,删除的62条也回来了。

    flashback table sphsy.login_table to timestamp to_timestamp(’2012-04-17 17:40:46′,’YYYY-MM-DD HH24:MI:SS’);

    ? 62 行

    select count(*)

    from sphsy.login_table a

    where a.id > 201204171078

    and a.id

    ? 删除之后的数据为3074,代表还有修改丢失。

    select count(*)

    from sphsy.login_table a

    where a.id >= 201204171141

    /*

    总结:方法C,方法D均可以用数据恢复。

    方法C安全,恢复麻烦。方法D简单,有可能数据丢失。

    */

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Oracle的Flashback用法汇总

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