Home Database Mysql Tutorial SQL 判断表是否已存在 【转】

SQL 判断表是否已存在 【转】

Jun 07, 2016 pm 03:14 PM
sql sqlserver judgment exist

sqlserver中 判断 表 是否 存在 分类: 数据库开发技术 sqlserver中 判断 表 是否 存在 在sqlserver(应该说在目前所有数据库产品)中创建一个资源如表,视图,存储过程中都要 判断 与创建的资源 是否 已经 存在 在sqlserver中一般可通过查询sys.objects系统表

 sqlserver中判断是否存在 

分类: 数据库开发技术

sqlserver中判断是否存在
在sqlserver(应该说在目前所有数据库产品)中创建一个资源如表,视图,存储过程中都要判断与创建的资源是否已经存在
在sqlserver中一般可通过查询sys.objects系统表来得知结果,不过可以有更方便的方法

如下:

if   object_id('tb_table') is not null 
print 'exist' else print'not exist'      

如上,可用object_id()来快速达到相同的目的,tb_table就是我将要创建的资源的名称,所以要先判断当前数据库中不存在相同的资源

object_id()可接受两个参数,第一个如上所示,代表资源的名称,上面的就是表的名字,但往往我们要说明我们所要创建的是什么类型的资源,


这样sql可以明确地在一种类型的资源中查找是否有重复的名字,如下:

if   object_id('tb_table','u') is not null 
 print 'exist' else print'not exist'

第二个参数 "u" 就表示tb_table是用户创建的表,即:USER_TABLE地首字母简写


查询sys.objects中可得到各种资源的类型名称(TYPE列),这里之举几个主要的例子
u  -----------  用户创建的表,区别于系统表(USER_TABLE)
s  -----------  系统表(SYSTEM_TABLE)
v  -----------  视图(VIEW)
p  -----------  存储过程(SQL_STORED_PROCEDURE)可使用select distinct type ,type_desc from sys.objects 获得全部信


原文地址: http://blog.csdn.net/fulianglove/archive/2008/08/07/2783381.aspx

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