Oracle中通过substr和instr实现截取指定字符之间的字符串:
摘要:在开发项目的过程中遇到了这样的一个问题,就是从远程服务器取到的数据中是由一段规则的字符串组成的,但是你想要的还不是这段字符串,是其中的一段字符串,那就的使用Oracle强大的函数了,我的问题是这样的,我要把如下所示红框内的那段字符串截取出
摘要:在开发项目的过程中遇到了这样的一个问题,就是从远程服务器取到的数据中是由一段规则的字符串组成的,但是你想要的还不是这段字符串,是其中的一段字符串,那就的使用Oracle强大的函数了,我的问题是这样的,我要把如下所示红框内的那段字符串截取出来,就是说截取第一个"-"和第二个“-”之间的字符串出来:
一:如图所示:
二:新建数据表:
CREATE TABLE test (name VARCHAR2 (32));
三:给表中插入数据:
insert into test values('CA-CA1344-A-11OCT141250-D'); insert into test values('JD-JD693-A-11OCT141105-D');
四:查询结果:
方式一:
select substr(name,instr(name,'-',1)+1,instr(name,'-',instr(name,'-',1)+1)-instr(name,'-',1)-1) from test;
方式二:
select substr(name,instr(name,'-',1,1)+1,instr(name,'-',1,2)-1-instr(name,'-',1,1)) from test;
五:结果如下:
六:接下我们再写一下,取第二个"-"到第三个"-"之间的字符串的方法:
select substr(name,instr(name,'-',2,2)+1,instr(name,'-',2,3)-1-instr(name,'-',2,2)) from test;
七:结果如下:

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