Home Database Mysql Tutorial sqlserver调用qqmap服务,根据地点获取所在城市

sqlserver调用qqmap服务,根据地点获取所在城市

Jun 07, 2016 pm 04:13 PM
sqlserver Place Serve Obtain transfer

sqlserver 调用qq map 服务,根据地点获取所在城市 首先需要解决的是如何在SQL SERVER中调用web service,其次是针对web service的返回json进行解析; 1、调用web service create proc getCityByPosition( @url varchar(2048) --Your Web Service Url (invoke

sqlserver 调用qq map 服务,根据地点获取所在城市

首先需要解决的是如何在SQL SERVER中调用web service,其次是针对web service的返回值json进行解析;

1、调用web service

create proc getCityByPosition(
    @url varchar(2048) --Your Web Service Url (invoked)
)
as
declare @Object as Int;
declare @ResponseText as Varchar(8000);
declare @resultStr varchar(2048)

-- exec getCityByPosition 'http://apis.map.qq.com/ws/geocoder/v1/?location=34.287100,117.255000&key=K76BZ-W3O2Q-RFL5S-GXOPR-3ARIT-6KFE5&output=json&&callback=?'

Exec sp_OACreate 'MSXML2.XMLHTTP', @Object OUT;
Exec sp_OAMethod @Object, 'open', NULL, 'get',@url,'false'
Exec sp_OAMethod @Object, 'send'
Exec sp_OAMethod @Object, 'responseText', @ResponseText OUTPUT
 
Select top 1 StringValue
    from parseJSON(@ResponseText) where name = 'city';

Exec sp_OADestroy @Object
Copy after login

执行测试可能报错,提示更改全局配置,需管理员执行下面代码:

sp_configure 'show advanced options', 1;
GO
RECONFIGURE;
GO
sp_configure 'Ole Automation Procedures', 1;
GO
RECONFIGURE;
GO
Copy after login

2、解析json字符串,使用自定义函数parseJSON

USE [pm_v3]
GO
/****** Object:  UserDefinedFunction [dbo].[parseJSON]    Script Date: 01/02/2015 18:06:05 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
       
      
    ALTER FUNCTION [dbo].[parseJSON]( @JSON NVARCHAR(MAX))  
    RETURNS @hierarchy TABLE  
      (  
       element_id INT IDENTITY(1, 1) NOT NULL, /* internal surrogate primary key gives the order of parsing and the list order */  
       parent_ID INT,/* if the element has a parent then it is in this column. The document is the ultimate parent, so you can get the structure from recursing from the document */  
       Object_ID INT,/* each list or object has an object id. This ties all elements to a parent. Lists are treated as objects here */  
       NAME VARCHAR(2000),/* the name of the object */  
       StringValue VARCHAR(MAX) NOT NULL,/*the string representation of the value of the element. */  
       ValueType VARCHAR(10) NOT null /* the declared type of the value represented as a string in StringValue*/  
      )  
    AS  
    BEGIN  
      DECLARE  
        @FirstObject INT, --the index of the first open bracket found in the JSON string  
        @OpenDelimiter INT,--the index of the next open bracket found in the JSON string  
        @NextOpenDelimiter INT,--the index of subsequent open bracket found in the JSON string  
 【本文来自鸿网互联 (http://www.68idc.cn)】       @NextCloseDelimiter INT,--the index of subsequent close bracket found in the JSON string  
        @Type NVARCHAR(10),--whether it denotes an object or an array  
        @NextCloseDelimiterChar CHAR(1),--either a '}' or a ']'  
        @Contents NVARCHAR(MAX), --the unparsed contents of the bracketed expression  
        @Start INT, --index of the start of the token that you are parsing  
        @end INT,--index of the end of the token that you are parsing  
        @param INT,--the parameter at the end of the next Object/Array token  
        @EndOfName INT,--the index of the start of the parameter at end of Object/Array token  
        @token NVARCHAR(200),--either a string or object  
        @value NVARCHAR(MAX), -- the value as a string  
        @name NVARCHAR(200), --the name as a string  
        @parent_ID INT,--the next parent ID to allocate  
        @lenJSON INT,--the current length of the JSON String  
        @characters NCHAR(36),--used to convert hex to decimal  
        @result BIGINT,--the value of the hex symbol being parsed  
        @index SMALLINT,--used for parsing the hex value  
        @Escape INT --the index of the next escape character  
          
       
      
      DECLARE @Strings TABLE /* in this temporary table we keep all strings, even the names of the elements, since they are 'escaped' in a different way, and may contain, unescaped, brackets denoting objects or lists. These are replaced in the JSON string by tokens representing the string */  
        (  
         String_ID INT IDENTITY(1, 1),  
         StringValue NVARCHAR(MAX)  
        )  
      SELECT--initialise the characters to convert hex to ascii  
        @characters='0123456789abcdefghijklmnopqrstuvwxyz',  
      /* firstly we process all strings. This is done because [{} and ] aren't escaped in strings, which complicates an iterative parse. */  
        @parent_ID=0;  
      WHILE 1=1 --forever until there is nothing more to do  
        BEGIN  
          SELECT  
            @start=PATINDEX('%[^a-zA-Z]["]%', @json);--next delimited string  
          IF @start=0 BREAK --no more so drop through the WHILE loop  
          IF SUBSTRING(@json, @start+1, 1)='"'   
            BEGIN --Delimited Name  
              SET @start=@Start+1;  
              SET @end=PATINDEX('%[^\]["]%', RIGHT(@json, LEN(@json+'|')-@start));  
            END  
          IF @end=0 --no end delimiter to last string  
            BREAK --no more  
          SELECT @token=SUBSTRING(@json, @start+1, @end-1)  
          --now put in the escaped control characters  
          SELECT @token=REPLACE(@token, FROMString, TOString)  
          FROM  
            (SELECT  
              '\"' AS FromString, '"' AS ToString  
             UNION ALL SELECT '\\', '\'  
             UNION ALL SELECT '\/', '/'  
             UNION ALL SELECT '\b', CHAR(08)  
             UNION ALL SELECT '\f', CHAR(12)  
             UNION ALL SELECT '\n', CHAR(10)  
             UNION ALL SELECT '\r', CHAR(13)  
             UNION ALL SELECT '\t', CHAR(09)  
            ) substitutions  
          SELECT @result=0, @escape=1  
      --Begin to take out any hex escape codes  
          WHILE @escape>0  
            BEGIN  
              SELECT @index=0,  
              --find the next hex escape sequence  
              @escape=PATINDEX('%\x[0-9a-f][0-9a-f][0-9a-f][0-9a-f]%', @token)  
              IF @escape>0 --if there is one  
                BEGIN  
                  WHILE @index<4 --there are always four digits to a \x sequence     
                    BEGIN   
                      SELECT --determine its value  
                        @result=@result+POWER(16, @index)  
                        *(CHARINDEX(SUBSTRING(@token, @escape+2+3-@index, 1),  
                                    @characters)-1), @index=@index+1 ;  
               
                    END  
                    -- and replace the hex sequence by its unicode value  
                  SELECT @token=STUFF(@token, @escape, 6, NCHAR(@result))  
                END  
            END  
          --now store the string away   
          INSERT INTO @Strings (StringValue) SELECT @token  
          -- and replace the string with a token  
          SELECT @JSON=STUFF(@json, @start, @end+1,  
                        &#39;@string&#39;+CONVERT(NVARCHAR(5), @@identity))  
        END  
      -- all strings are now removed. Now we find the first leaf.    
      WHILE 1=1  --forever until there is nothing more to do  
      BEGIN  
       
      
      SELECT @parent_ID=@parent_ID+1  
      --find the first object or list by looking for the open bracket  
      SELECT @FirstObject=PATINDEX(&#39;%[{[[]%&#39;, @json)--object or array  
      IF @FirstObject = 0 BREAK  
      IF (SUBSTRING(@json, @FirstObject, 1)=&#39;{&#39;)   
        SELECT @NextCloseDelimiterChar=&#39;}&#39;, @type=&#39;object&#39;  
      ELSE   
        SELECT @NextCloseDelimiterChar=&#39;]&#39;, @type=&#39;array&#39;  
      SELECT @OpenDelimiter=@firstObject  
       
      
      WHILE 1=1 --find the innermost object or list...  
        BEGIN  
          SELECT  
            @lenJSON=LEN(@JSON+&#39;|&#39;)-1  
      --find the matching close-delimiter proceeding after the open-delimiter  
          SELECT  
            @NextCloseDelimiter=CHARINDEX(@NextCloseDelimiterChar, @json,  
                                          @OpenDelimiter+1)  
      --is there an intervening open-delimiter of either type?  
          SELECT @NextOpenDelimiter=PATINDEX(&#39;%[{[[]%&#39;,  
                 RIGHT(@json, @lenJSON-@OpenDelimiter))--object  
          IF @NextOpenDelimiter=0 --then we are done.  
            BREAK  
          SELECT @NextOpenDelimiter=@NextOpenDelimiter+@OpenDelimiter  
          IF @NextCloseDelimiter<@NextOpenDelimiter --we have found the next leaf  
            BREAK   
          --we prepare to walk the document further  
          IF SUBSTRING(@json, @NextOpenDelimiter, 1)=&#39;{&#39;   
            SELECT @NextCloseDelimiterChar=&#39;}&#39;, @type=&#39;object&#39;  
          ELSE   
            SELECT @NextCloseDelimiterChar=&#39;]&#39;, @type=&#39;array&#39;  
          SELECT @OpenDelimiter=@NextOpenDelimiter  
        END  
      /*and now we can parse out the list or name/value pairs. We first pull out the structure into the variable &#39;@contents&#39; and replace it in the JSON document with a token representing it.*/  
      SELECT  
        @contents=SUBSTRING(@json, @OpenDelimiter+1,  
                            @NextCloseDelimiter-@OpenDelimiter-1)  
      SELECT  
        @JSON=STUFF(@json, @OpenDelimiter,  
                    @NextCloseDelimiter-@OpenDelimiter+1,  
                    &#39;@&#39;+@type+CONVERT(NVARCHAR(5), @parent_ID))  
     /*and do each name/value pair, or just value, in the case of an ordered value list.  */              
      WHILE (PATINDEX(&#39;%[A-Za-z0-9@+.e]%&#39;, @contents))<>0   
        BEGIN  
          IF @Type=&#39;Object&#39; /*it will be a 0-n list containing a string followed by a string, number,boolean, or null*/  
            BEGIN  
              SELECT  
                @end=CHARINDEX(&#39;:&#39;, &#39; &#39;+@contents) /*if there is anything, it will be a string-based name.*/  
              SELECT  @start=PATINDEX(&#39;%[^A-Za-z@][@]%&#39;, &#39; &#39;+@contents)--find out what the token is  
              SELECT @token=SUBSTRING(&#39; &#39;+@contents, @start+1, @End-@Start-1),  
                @endofname=PATINDEX(&#39;%[0-9]%&#39;, @token),--and find out the number so as to fish out the string  
                @param=RIGHT(@token, LEN(@token)-@endofname+1)  
              SELECT--separate the token from the contents of the structure (chop, chop0  
                @token=LEFT(@token, @endofname-1),  
                @Contents=RIGHT(&#39; &#39;+@contents, LEN(&#39; &#39;+@contents+&#39;|&#39;)-@end-1)  
              --now we get the string we have stored (names are stored as strings)  
              SELECT  @name=stringvalue FROM @strings  
                WHERE string_id=@param --fetch the name  
            END  
          ELSE --it is merely a value in an ordered list, without a name  
            SELECT @Name=null    
          SELECT  
            @end=CHARINDEX(&#39;,&#39;, @contents)-- a string-token, object-token, list-token, number,boolean, or null  
          IF @end=0 --then we&#39;re at the end of the list  
            SELECT @end=PATINDEX(&#39;%[A-Za-z0-9@+.e][^A-Za-z0-9@+.e]%&#39;, @Contents+&#39; &#39;)  
              +1  
          SELECT @start=PATINDEX(&#39;%[^A-Za-z0-9@+.e][A-Za-z0-9@+.e]%&#39;, &#39; &#39;+@contents)  
          SELECT --get the value and snip the contents  
            @Value=RTRIM(SUBSTRING(@contents, @start, @End-@Start)),  
            @Contents=RIGHT(@contents+&#39; &#39;, LEN(@contents+&#39;|&#39;)-@end)  
          IF SUBSTRING(@value, 1, 7)=&#39;@object&#39;   
            INSERT INTO @hierarchy  
              (NAME, parent_ID, StringValue, Object_ID, ValueType)  
              SELECT @name, @parent_ID, SUBSTRING(@value, 8, 5),  
                SUBSTRING(@value, 8, 5), &#39;object&#39;   
          ELSE   
            IF SUBSTRING(@value, 1, 6)=&#39;@array&#39;   
              INSERT INTO @hierarchy  
                (NAME, parent_ID, StringValue, Object_ID, ValueType)  
                SELECT @name, @parent_ID, SUBSTRING(@value, 7, 5),  
                  SUBSTRING(@value, 7, 5), &#39;array&#39;   
            ELSE   
              IF SUBSTRING(@value, 1, 7)=&#39;@string&#39; --it is a string  
                INSERT INTO @hierarchy  
                  (NAME, parent_ID, StringValue, ValueType)  
                  SELECT @name, @parent_ID, stringvalue, &#39;string&#39;  
                  FROM @strings  
                  WHERE string_id=SUBSTRING(@value, 8, 5)  
              ELSE   
                IF @value IN (&#39;true&#39;, &#39;false&#39;)--a boolean!   
                  INSERT INTO @hierarchy  
                    (NAME, parent_ID, StringValue, ValueType)  
                    SELECT @name, @parent_ID, @value, &#39;boolean&#39;  
                ELSE   
                  IF @value=&#39;null&#39; --it is a null  
                    INSERT INTO @hierarchy  
                      (NAME, parent_ID, StringValue, ValueType)  
                      SELECT @name, @parent_ID, @value, &#39;null&#39;  
                  ELSE   
                    IF PATINDEX(&#39;%[^0-9]%&#39;, @value)>0 --a real number  
                      INSERT INTO @hierarchy  
                        (NAME, parent_ID, StringValue, ValueType)  
                        SELECT @name, @parent_ID, @value, &#39;real&#39;  
                    ELSE --it must be an INT  
                      INSERT INTO @hierarchy  
                        (NAME, parent_ID, StringValue, ValueType)  
                        SELECT @name, @parent_ID, @value, &#39;int&#39;  
       
      
        END  
      END  
    --and so lastly we put the root into the hierarchy.  
    INSERT INTO @hierarchy (NAME, parent_ID, StringValue, Object_ID, ValueType)  
      SELECT &#39;-&#39;, NULL, &#39;&#39;, @parent_id-1, @type  
    --  
       RETURN  
    END  
Copy after login


Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn

Hot AI Tools

Undresser.AI Undress

Undresser.AI Undress

AI-powered app for creating realistic nude photos

AI Clothes Remover

AI Clothes Remover

Online AI tool for removing clothes from photos.

Undress AI Tool

Undress AI Tool

Undress images for free

Clothoff.io

Clothoff.io

AI clothes remover

Video Face Swap

Video Face Swap

Swap faces in any video effortlessly with our completely free AI face swap tool!

Hot Tools

Notepad++7.3.1

Notepad++7.3.1

Easy-to-use and free code editor

SublimeText3 Chinese version

SublimeText3 Chinese version

Chinese version, very easy to use

Zend Studio 13.0.1

Zend Studio 13.0.1

Powerful PHP integrated development environment

Dreamweaver CS6

Dreamweaver CS6

Visual web development tools

SublimeText3 Mac version

SublimeText3 Mac version

God-level code editing software (SublimeText3)

How to import mdf file into sqlserver How to import mdf file into sqlserver Apr 08, 2024 am 11:41 AM

The import steps are as follows: Copy the MDF file to SQL Server's data directory (usually C:\Program Files\Microsoft SQL Server\MSSQL\DATA). In SQL Server Management Studio (SSMS), open the database and select Attach. Click the Add button and select the MDF file. Confirm the database name and click the OK button.

How to solve the problem that the object named already exists in the sqlserver database How to solve the problem that the object named already exists in the sqlserver database Apr 05, 2024 pm 09:42 PM

For objects with the same name that already exist in the SQL Server database, the following steps need to be taken: Confirm the object type (table, view, stored procedure). IF NOT EXISTS can be used to skip creation if the object is empty. If the object has data, use a different name or modify the structure. Use DROP to delete existing objects (use caution, backup recommended). Check for schema changes to make sure there are no references to deleted or renamed objects.

What to do if the sqlserver service cannot be started What to do if the sqlserver service cannot be started Apr 05, 2024 pm 10:00 PM

When the SQL Server service fails to start, here are some steps to resolve: Check the error log to determine the root cause. Make sure the service account has permission to start the service. Check whether dependency services are running. Disable antivirus software. Repair SQL Server installation. If the repair does not work, reinstall SQL Server.

How to check sqlserver port number How to check sqlserver port number Apr 05, 2024 pm 09:57 PM

To view the SQL Server port number: Open SSMS and connect to the server. Find the server name in Object Explorer, right-click it and select Properties. In the Connection tab, view the TCP Port field.

How to recover accidentally deleted database in sqlserver How to recover accidentally deleted database in sqlserver Apr 05, 2024 pm 10:39 PM

If you accidentally delete a SQL Server database, you can take the following steps to recover: stop database activity; back up log files; check database logs; recovery options: restore from backup; restore from transaction log; use DBCC CHECKDB; use third-party tools. Please back up your database regularly and enable transaction logging to prevent data loss.

Where is the sqlserver database? Where is the sqlserver database? Apr 05, 2024 pm 08:21 PM

SQL Server database files are usually stored in the following default location: Windows: C:\Program Files\Microsoft SQL Server\MSSQL\DATALinux: /var/opt/mssql/data The database file location can be customized by modifying the database file path setting.

How to delete sqlserver if the installation fails? How to delete sqlserver if the installation fails? Apr 05, 2024 pm 11:27 PM

If the SQL Server installation fails, you can clean it up by following these steps: Uninstall SQL Server Delete registry keys Delete files and folders Restart the computer

How to change sqlserver English installation to Chinese How to change sqlserver English installation to Chinese Apr 05, 2024 pm 10:21 PM

SQL Server English installation can be changed to Chinese by following the following steps: download the corresponding language pack; stop the SQL Server service; install the language pack; change the instance language; change the user interface language; restart the application.

See all articles