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Oracle_5 ROWNUM Create New User 备份一张表

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Release: 2016-06-07 16:59:38
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Rownum是oracle为每个表附加的一个尾字段,它记录着每一行的行号。Oracle的一个缺陷就是rownum只能和rsquo;lt;rsquo;或者rsq

Rownum是Oracle为每个表附加的一个尾字段,它记录着每一行的行号。Oracle的一个缺陷就是rownum只能和’

求薪水最高的前5名

select ename,sal
from ( select ename,sal
from emp
order by sal desc)
where rownum

求薪水的第

select ename,sal
from ( select ename,sal,rownum r
       from (select ename,sal
             from emp
             order by sal desc)
     )
where r=6;

Create New User

首先备份( backup scott),在命令行下输入以下命令,按提示操作

exp

然后创建用户 create user,在sqlplus下切换到管理员用户,输入

create user USER_NAME(such as:lue) identified by password(lue) default tablespace users quota(配额) 10M on users即是给用户分配10M的空间

其次是分配新建用户的权限,命令:

grant create session(登陆权限),creat table,create view to lue

最后导入数据 import the data,在命令行下输入以下命令,按提示操作;

imp

一道SQL面试题

有3张表S,C,SC

S(sno,sname) 代表(学号,姓名)

C(cno,cname,cteacher)代表(课程号,课程名,,教室)

SC(sno,cno,scgrade)代表(学号,课程号,成绩)

问题:

1,  找出没有选过“liming”老师的所有学生的姓名

2,  列出2门以上(含2门)不及格学生姓名及平均成绩

3,  学过1号课程又学过2号课程所有学生的姓名

答案:

//Answer 1:
select sname
from S join SC on(s.sno = sc.sno) join C (c.cno = sc.cno)
where C.cteacher ‘liming’;
//answer 2:
select sname
where sno in (select sno,count(*)
from SC
where scgrade group by sno
having count(*) >1);
//answer 3:
//方法1:
select sname
from S join (select sno
from SC
where C.cno = 1 and C.cno = 2) t
      on (S.sno = t.sno);
//方法2:
select  sname
from S
where sno in(select sno
     from SC
     where cno = 1 and cno in (select distinct sno
        from SC
        where cno = 2)
           );

linux

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