php判断页面是否是微信打开的示例(微信打开网页)_php实例
$user_agent = $_SERVER['HTTP_USER_AGENT'];
if (strpos($user_agent, 'MicroMessenger') === false) {
// 非微信浏览器禁止浏览
echo "HTTP/1.1 401 Unauthorized";
} else {
// 微信浏览器,允许访问
echo "MicroMessenger";
// 获取版本号
preg_match('/.*?(MicroMessenger\/([0-9.]+))\s*/', $user_agent, $matches);
echo '
Version:'.$matches[2];
}
好吧,我也不能直接反驳,不过,这个确实非常不靠谱、
拿数据说话吧。
下面分别是 Android, WinPhone, iPhone 的 HTTP_USER_AGENT 信息。
"HTTP_USER_AGENT": "Mozilla/5.0 (Linux; U; Android 4.1; zh-cn; Galaxy Nexus Build/Wind-Galaxy Nexus-V1.2) AppleWebKit/534.30 (KHTML, like Gecko) Version/4.0 Mobile Safari/534.30 MicroMessenger/5.0.1.352",
"HTTP_USER_AGENT": "Mozilla/5.0 (compatible; MSIE 10.0; Windows Phone 8.0; Trident/6.0; IEMobile/10.0; ARM; Touch; NOKIA; Nokia 920T)",
"HTTP_USER_AGENT": "Mozilla/5.0 (iPhone; CPU iPhone OS 6_1_3 like Mac OS X) AppleWebKit/536.26 (KHTML, like Gecko) Mobile/10B329 MicroMessenger/5.0.1",
可以看到 WinPhone 根本就没有 MicroMessenger 所以无法判断、其实 userAgent 判断本来就是很假的事情、所以我觉得应该用 js 判断是否存在 WeixinJSBridge ,然后 ajax 给 php
php检测到了然后返回真正的页面信息、期间加一个 “玩命加载中...” 这样就很和谐了、当然 ajax 的话,也是可以欺骗的,但是相对 userAgent 欺骗来说,就要麻烦一点了、
不过我们的目的是检测是否是微信端,而不是欺骗的问题、具体代码我就不写了,因为最讨厌那种拿来主义了、无限的复制黏贴,而且有时候代码被过滤了一部分也不管、

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