How javaScript generates xmlhttp_javascript tips

Copy code The code is as follows:

function ajaxFunction(){
var xmlHttp;
try { // Firefox, Opera 8.0, Safari
xmlHttp = new XMLHttpRequest();
}
catch (e) {
try {// Internet Explorer
xmlHttp = new ActiveXObject("Msxml2 .XMLHTTP");
}
catch (e) {
try {
xmlHttp = new ActiveXObject("Microsoft.XMLHTTP");
}
catch (e) {
}
}
}

return xmlHttp;
}