mysql中sql实现查询当天、昨天、本月、季度的语句-Mysql Tutorial-php.cn

mysql中sql实现查询当天、昨天、本月、季度的语句

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Release： 2016-06-07 17:52:10

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本文章收藏了关于mysql中sql实现查询当天、昨天、本月、季度的语句，有需要学习的朋友可参考一下。

代码如下

复制代码

查询

今天
select * from 表名 where to_days(时间字段名) = to_days(now());
昨天

SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) – TO_DAYS( 时间字段名) 7天

SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) 近30天

SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY)

本月

SELECT * FROM 表名 WHERE DATE_FORMAT( 时间字段名, ‘%Y%m’ ) = DATE_FORMAT( CURDATE( ) , ‘%Y%m’ )
上一月

SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , ‘%Y%m’ ) , date_format( 时间字段名, ‘%Y%m’ ) ) =1
同时，再附上一个 mysql官方的相关document

#查询本季度数据
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now());
#查询上季度数据
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));
#查询本年数据
select * from `ht_invoice_information` where YEAR(create_date)=YEAR(NOW());
#查询上年数据
select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year));

查询当前这周的数据
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now());

查询上周的数据
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1;

查询当前月份的数据
select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(now(),'%Y-%m')

查询距离当前现在6个月的数据
select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();

查询上个月的数据
select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m')

select * from ` user ` where DATE_FORMAT(pudate, ' %Y%m ' ) = DATE_FORMAT(CURDATE(), ' %Y%m ' ) ;

select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now())

select *
from user
where MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now())

select *
from [ user ]
where YEAR (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = YEAR (now())
and MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now())

select *
from [ user ]
where pudate between 上月最后一天
and 下月第一天

where date(regdate) = curdate();

select * from test where year(regdate)=year(now()) and month(regdate)=month(now()) and day(regdate)=day(now())

SELECT date( c_instime ) ,curdate( )
FROM `t_score`
WHERE 1
LIMIT 0 , 30

http://dev.mysql.com/doc/refman/5.1/zh/tutorial.html