用PHP将一个数组存到数据库的一个字段的方法
在工作项目中有一个需求,要把数一些数据转成数组,然后再存到数库库一个字段中,个人目前知道两种方法,一种是用序列化函数serialize($arr);,还有一种是用php的json扩展自带的函数json_encode($arr);。
要把数一个数组,存到数据库的一个字段中,有两种方法,一种是用序列化函数serialize($arr);还有一种是用php的json扩展自带的函数json_encode($arr);如果json_encode对含有中文的字符进行编码时,会自动转换成unicode编码。就像这样:a:2:{s:4:”code”;s:1:”1″;s:3:”msg”;s:9:”PHP日志”;},虽然js上能正常处理,但是看起来还是不那爽,在PHP的官方网站上面找到一个函数,可以解决这个问题,也就是将数据转换json,而且中文不会被转换为unicode码。
代码如下 | 复制代码 |
function php2js($a=false) { if (is_null($a)) return 'null'; if ($a === false) return 'false'; if ($a === true) return 'true'; if (is_scalar($a)) { if (is_float($a)) { // Always use "." for floats. $a = str_replace(",", ".", strval($a)); } // All scalars are converted to strings to avoid indeterminism. // PHP's "1" and 1 are equal for all PHP operators, but // JS's "1" and 1 are not. So if we pass "1" or 1 from the PHP backend, // we should get the same result in the JS frontend (string). // Character replacements for JSON. static $jsonReplaces = array(array("", "/", "n", "t", "r", "b", "f", '"'), array('\', '/', 'n', 't', 'r', 'b', 'f', '"')); return '"' . str_replace($jsonReplaces[0], $jsonReplaces[1], $a) . '"'; } $isList = true; for ($i = 0, reset($a); $i { if (key($a) !== $i) { $isList = false; break; } } $result = array(); if ($isList) { foreach ($a as $v) $result[] = php2js($v); return '[ ' . join(', ', $result) . ' ]'; } else { foreach ($a as $k => $v) $result[] = php2js($k).': '.php2js($v); return '{ ' . join(', ', $result) . ' }'; } } ?> |
使用方法一:
echo serialize(array(‘code’=>’1′,’msg’=>’PHP日志’));
输出:a:2:{s:4:”code”;s:1:”1″;s:3:”msg”;s:9:”PHP日志”;}
使用方法二:
echo json_encode(array(‘code’=>’1′,’msg’=>’PHP日志’));
输出:{“code”:”1″,”msg”:”PHPu65e5u5fd7″}
使用方法三:
echo php2js(array(‘code’=>’1′,’msg’=>’未知错误’));
输出:{ “code”: “1”, “msg”: “PHP日志” }

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