菜鸟使用python实现正则检测密码合法性
客户系统升级,要求用户密码符合一定的规则,即:包含大小写字母、数字、符号,长度不小于8,于是先用python写了个简单的测试程序:
在写解决方案前,列一下
python正则表达式中的特殊字符:
^ 表示匹配的字符必须在最前边
$ 表示匹配的字符必须在最后边
* 匹配* 前面的字符0次或n次
+ 匹配+ 前面的字符1次或n次
? 匹配?前面的字符0次或1次
. (小数点)匹配除换行符外的所有字符
(x) 匹配x并记录匹配的值
x|y 匹配x或者y
{n} 这里n是一个正整数。匹配前面的n个字符
{n,} 这里n是一个正整数。匹配至少n个前面的字符
{n,m} 这里n和m都是正整数。匹配至少n个、最多m个前面的字符
[xyz] 字符列表,匹配表中的任一字符,可以通过连接字符 - 指出字符范围,如 [a-z] 表示所有小写字符
[b] 匹配一个空格
b 匹配一个单词的分界线,比如一个空格
B 匹配一个单词的非分界线
re模块匹配规则(re.match函数的第三个参数):
re.IGNORECASE 忽略文中的大小写
re.LOCALE 处理字符集本地化
re.MULTILINE 是否支持多行匹配
re.DOTALL 匹配一些特殊标记,例如使用.匹配\n等字符
re.VERBOSE 忽略正则表达式中的空格或者换行等字符
re.UNICODE 使用Unicode编码
#encoding=utf-8 #------------------------------------------------------------------------------- # Name: 模块1 # Purpose: # # Author: Administrator # # Created: 10-06-2014 # Copyright: (c) Administrator 2014 # Licence: <your licence> #------------------------------------------------------------------------------- import re def checklen(pwd): return len(pwd)>=8 def checkContainUpper(pwd): pattern = re.compile('[A-Z]+') match = pattern.findall(pwd) if match: return True else: return False def checkContainNum(pwd): pattern = re.compile('[0-9]+') match = pattern.findall(pwd) if match: return True else: return False def checkContainLower(pwd): pattern = re.compile('[a-z]+') match = pattern.findall(pwd) if match: return True else: return False def checkSymbol(pwd): pattern = re.compile('([^a-z0-9A-Z])+') match = pattern.findall(pwd) if match: return True else: return False def checkPassword(pwd): #判断密码长度是否合法 lenOK=checklen(pwd) #判断是否包含大写字母 upperOK=checkContainUpper(pwd) #判断是否包含小写字母 lowerOK=checkContainLower(pwd) #判断是否包含数字 numOK=checkContainNum(pwd) #判断是否包含符号 symbolOK=checkSymbol(pwd) print(lenOK) print(upperOK) print(lowerOK) print(numOK) print(symbolOK) return (lenOK and upperOK and lowerOK and numOK and symbolOK) def main(): if checkPassword('Helloworld#123'): print('检测通过') else: print('检测未通过') if __name__ == '__main__': main()
平时用正则不多,不知道怎么写一个正则满足要求,用了比较笨的办法,谁知道一句正则检验的请赐教!
我们再来看一个稍微复杂些的 检测邮箱名及密码验证
代码:
main.py
# coding=gbk import re def ProcessMail(inputMail): isMatch = bool(re.match(r"^[a-zA-Z](([a-zA-Z0-9]*\.[a-zA-Z0-9]*)|[a-zA-Z0-9]*)[a-zA-Z]@([a-z0-9A-Z]+\.)+[a-zA-Z]{2,}$", inputMail,re.VERBOSE)); if isMatch: print ("邮箱注册成功。"); else: print ("邮箱注册失败。"); return isMatch; def ProcessPassword(inputPassword): #处理正则表达式 isMatch = bool(re.match(r"[a-zA-Z0-9]{8}",inputPassword,flags=0)); #用type的三位表示数字type[0],小写字母type[1],大写字母type[2]是否都具备 if isMatch: type = [False,False,False] for i in range(0,8): temp = inputPassword[i] if ord(temp) >= ord('0') and ord(temp) <= ord('9'): type[0] = True; elif ord(temp) >= ord('a') and ord(temp) <= ord('z'): type[1] = True; elif ord(temp) >= ord('A') and ord(temp) <= ord('Z'): type[2] = True; for i in type: if i is False: isMatch = False; break; #处理是否有重复的字符出现 if isMatch: for i in range(0,7): temp = inputPassword[i]; for j in range(i + 1,8): if inputPassword[j] == temp: isMatch = False; break; if isMatch: print ("密码注册成功。"); else: print ("密码注册失败。"); return isMatch; if __name__ == '__main__': mailState = False; while mailState is False: inputMail = input("输入邮箱: "); mailState = ProcessMail(inputMail); print ("\n"); # passwordState = False; while passwordState is False: inputPassword = input("输入密码: "); passwordState = ProcessPassword(inputPassword); print ("\n");
输出:
输入邮箱: a.a9@sina.com 邮箱注册失败。 输入邮箱: 9a.aa@sina.com 邮箱注册失败。 输入邮箱: a.a.a@sina.com 邮箱注册失败。 输入邮箱: a9999@sina.com 邮箱注册失败。 输入邮箱: a123.banana@..com 邮箱注册失败。 输入邮箱: a123.banana@a..com 邮箱注册失败。 输入邮箱: a123.banana@sina.c 邮箱注册失败。 输入邮箱: a123.banana@sina.com 邮箱注册失败。 输入邮箱: a123.banana@sina.com 邮箱注册成功。
密码的测试也满足需求,不一一列举

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