python开发中module模块用法实例分析
本文实例讲述了python开发中module模块用法。分享给大家供大家参考，具体如下：
在python中，我们可以把一些功能模块化，就有一点类似于java中，把一些功能相关或者相同的代码放到一起，这样我们需要用的时候，就可以直接调用了
这样做的好处：
1,只要写好了一个功能模块，就可以在以后调用，代码的重用就可以体现出来了
2,功能写好了以后，不会发生错误。如果一个相同的功能，我们在一个模块中写了一遍，在另外的模块中又写了一遍......这样我们难免保证我们在写的过程中不发生错误。
但是我们如果能够写一个功能模块写好了以后，就把他用在很多地方，其一，用起来方便，其二，可以保证其正确性
3,代码共享
说了这么多，还是来点实际的比较好！！！
我们新建一个文件：fibo.py（当然这个名字可以随个人意愿）
#Modules
def fib(n): # write Fibonacci series up to n
a,b = 0,1
while b < n:
print(b,end=' ')
a,b = b, a + b
print()
def fib2(n): # return Fibonacci series up to n
result = []
a,b = 0,1
while b < n:
result.append(b)
a,b = b, a + b
return result
def add(numberA,numberB): #定义加法
return numberA + numberB
def sub(numberA,numberB): #定义减法
return numberA - numberB
def mul(numberA,numberB): #定义乘法
return numberA*numberB
def div(numberA,numberB): #定义除法
if numberB != 0:
return numberA//numberB
else:
return 'Error'
上面就是我们自定义的一个简单的功能模块，里面定义了一些方法。
我们需要在：test_modules.py(和fibo.py文件在同一个目录的另一个文件)文件中调用fibo.py中的方法：
import fibo fibo.fib(1000) result = fibo.fib2(1000) print(result)
运行效果如下：
Python 3.3.2 (v3.3.2:d047928ae3f6, May 16 2013, 00:03:43) [MSC v.1600 32 bit (Intel)] on win32 Type "copyright", "credits" or "license()" for more information. >>> ================================ RESTART ================================ >>> 1 2 3 5 8 13 21 34 55 89 144 233 377 610 987 [1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610, 987] >>>
现在我们又定义了一个文件：
test_modules1.py调用fibo.py中的部分方法
from fibo import fib,fib2 #这里是可以直接使用以上两个方法的 fib(100) result = fib2(1000) print(result)
上面描述的是，我们应用了fibo.py文件中的fib，fib2两个方法
运行效果：
Python 3.3.2 (v3.3.2:d047928ae3f6, May 16 2013, 00:03:43) [MSC v.1600 32 bit (Intel)] on win32 Type "copyright", "credits" or "license()" for more information. >>> ================================ RESTART ================================ >>> 1 2 3 5 8 13 21 34 55 89 [1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610, 987] >>>
如果我们要应用fibo.py中的所有方法，我们可以这样做：
#应用fibo.py中所有的方法
#有一点类似于java中的引入包的形式
from fibo import *
#这里可以使用fibo中的所用方法
fib(1000)
print(fib2(100))
numberA = 20
numberB = 5
print('加法计算：',numberA,'+',numberB,'=',add(numberA,numberB))
print('减法计算：',numberA,'-',numberB,'=',sub(numberA,numberB))
print('乘法计算：',numberA,'*',numberB,'=',mul(numberA,numberB))
print('除法计算：',numberA,'/',numberB,'=',div(numberA,numberB))
运行效果：
Python 3.3.2 (v3.3.2:d047928ae3f6, May 16 2013, 00:03:43) [MSC v.1600 32 bit (Intel)] on win32 Type "copyright", "credits" or "license()" for more information. >>> ================================ RESTART ================================ >>> 1 2 3 5 8 13 21 34 55 89 144 233 377 610 987 [1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89] 加法计算： 20 + 5 = 25 减法计算： 20 - 5 = 15 乘法计算： 20 * 5 = 100 除法计算： 20 / 5 = 4 >>>
希望本文所述对大家Python程序设计有所帮助。
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