Python压缩解压缩zip文件及破解zip文件密码的方法

python 的 zipfile 提供了非常便捷的方法来压缩和解压 zip 文件。

例如，在py脚本所在目录中，有如下文件：

readability/readability.js
readability/readability.txt
readability/readability-print.css
readability/sprite-readability.png
readability/readability.css

将 readability 目录中的文件压缩到脚本所在目录的 readability.zip 文件中，保持相同的文件结构，然后打印出生成的压缩包 的文件列表，再用两种方式分别解压文件到脚本所在目录的 output 目录和 output/bak 目录中。

脚本如下：

#!/usr/vin/env python
# coding: utf-8
"""
压缩和解压zip文件
"""

import os
import zipfile

def compress(zip_file, input_dir):
  f_zip = zipfile.ZipFile(zip_file, 'w')
  for root, dirs, files in os.walk(input_dir):
    for f in files:
      # 获取文件相对路径，在压缩包内建立相同的目录结构
      abs_path = os.path.join(os.path.join(root, f))
      rel_path = os.path.relpath(abs_path, os.path.dirname(input_dir))
      f_zip.write(abs_path, rel_path, zipfile.ZIP_STORED)

def extract(zip_file, output_dir):
  f_zip = zipfile.ZipFile(zip_file, 'r')

  # 解压所有文件到指定目录
  f_zip.extractall(output_dir)

  # 逐个解压文件到指定目录
  for f in f_zip.namelist():
    f_zip.extract(f, os.path.join(output_dir, 'bak'))

def printdir(zip_file):
  f_zip = zipfile.ZipFile(zip_file, 'r')
  print '== printdir() ============================'
  f_zip.printdir()
  print
  print '== namelist() ============================'
  for f in f_zip.namelist():
    print f

if __name__ == '__main__':
  zip_file = 'readability.zip'
  compress(zip_file, os.path.join(os.getcwd(), 'readability'))
  printdirzip_file)
  extract(zip_file, 'output')

python暴力破解含密码的zip压缩文件
思路:

1.先自己生成一份txt的密码字典

2.然后读取出来，一个个的尝试,当密码错误是，程序会报错中断，所以密码错误，要使用pass

3.当解压缩成功后，中断程序，输出正确密码

import zipfile
import os
from threading import Thread
import time
#压缩文件的路径
path = r'C:\Users\Administrator\Desktop\moeMaid-master.zip'
#password='1234'

def pojie_zip(path,password):
 if path[-4:]=='.zip':
  #path = dir+ '\\' +file
  #print path
  zip = zipfile.ZipFile(path, "r",zipfile.zlib.DEFLATED)
  #print zip.namelist()
  try:
   #若解压成功，则返回True,和密码
   zip.extractall(path='C:\\Users\\Administrator\\Desktop\\',members=zip.namelist() , pwd=password)
   print ' ----success!,The password is %s' % password
   zip.close()
   return True
  except:
   pass #如果发生异常，不报错
  print 'error'
  
  
def get_pass():
 #密码字典的路径
 passPath='C:\\Users\\Administrator\\Desktop\\zip.txt'
 passFile=open(passPath,'r')
 for line in passFile.readlines():
  password=line.strip('\n')
  print 'Try the password %s' % password
  if pojie_zip(path,password):
   break
 passFile.close()
if __name__=='__main__':
 start=time.clock()
 get_pass()
 print "done (%.2f seconds)" % (time.clock() - start)

这是我解压缩一个5.4M文件的速度，其实时间都花在了解压缩上了

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