Python的ORM框架中SQLAlchemy库的查询操作的教程-Python Tutorial-php.cn

1. 返回列表和标量(Scalar)

前面我们注意到Query对象可以返回可迭代的值(iterator value)，然后我们可以通过for in来查询。不过Query对象的all()、one()以及first()方法将返回非迭代值(non-iterator value)，比如说all()返回的是一个列表：

>>> query = session.query(User).\
>>>     filter(User.name.like('%ed')).order_by(User.id)
>>> query.all() 
SELECT users.id AS users_id,
    users.name AS users_name,
    users.fullname AS users_fullname,
    users.password AS users_password
FROM users
WHERE users.name LIKE &#63; ORDER BY users.id
('%ed',)
 
[User('ed','Ed Jones', 'f8s7ccs'), User('fred','Fred Flinstone', 'blah')]

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first()方法限制并仅作为标量返回结果集的第一条记录：

>>> query.first() 
SELECT users.id AS users_id,
    users.name AS users_name,
    users.fullname AS users_fullname,
    users.password AS users_password
FROM users
WHERE users.name LIKE &#63; ORDER BY users.id
 LIMIT &#63; OFFSET &#63;
('%ed', 1, 0)
 
<User('ed','Ed Jones', 'f8s7ccs')>

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one()方法，完整的提取所有的记录行，并且如果没有明确的一条记录行(没有找到这条记录)或者结果中存在多条记录行，将会引发错误异常NoResultFound或者MultipleResultsFound：

>>> from sqlalchemy.orm.exc import MultipleResultsFound
>>> try: 
...   user = query.one()
... except MultipleResultsFound, e:
...   print e
SELECT users.id AS users_id,
    users.name AS users_name,
    users.fullname AS users_fullname,
    users.password AS users_password
FROM users
WHERE users.name LIKE &#63; ORDER BY users.id
('%ed',)
 
Multiple rows were found for one()

>>> from sqlalchemy.orm.exc import NoResultFound
>>> try: 
...   user = query.filter(User.id == 99).one()
... except NoResultFound, e:
...   print e
SELECT users.id AS users_id,
    users.name AS users_name,
    users.fullname AS users_fullname,
    users.password AS users_password
FROM users
WHERE users.name LIKE &#63; AND users.id = &#63; ORDER BY users.id
('%ed', 99)
 
No row was found for one()

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2. 使用原义SQL (Literal SQL)

Query对象能够灵活的使用原义SQL查询字符串作为查询参数，比如我们之前用过的filter()和order_by()方法：

>>> for user in session.query(User).\
...       filter("id<224").\
...       order_by("id").all(): 
...   print user.name
SELECT users.id AS users_id,
    users.name AS users_name,
    users.fullname AS users_fullname,
    users.password AS users_password
FROM users
WHERE id<224 ORDER BY id
()
 
ed
wendy
mary
fred

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当然很多人可能会和我感觉一样，会有些不适应，因为使用ORM就是为了摆脱SQL语句的，没想到现在又看到SQL的影子了。呵呵，SQLAlchemy也要照顾到使用上的灵活性嘛，毕竟有些查询语句直接编入要容易得多。

当然绑定参数也可以用基于字符串的SQL指派，使用冒号来标记替代参数，然后再使用params()方法指定相应的值：

>>> session.query(User).filter("id<:value and name=:name").\
...   params(value=224, name='fred').order_by(User.id).one() 
SELECT users.id AS users_id,
    users.name AS users_name,
    users.fullname AS users_fullname,
    users.password AS users_password
FROM users
WHERE id<User('fred','Fred Flinstone', 'blah')>

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到这里，SQL语句的样子已经初见端倪了，其实我们可以更极端一点，直接使用SQL语句，什么？这样就失去ORM的价值了！别急，这里只是介绍一下支持这种用法，当然我建议不到万不得已，尽量不要这样写，因为可能会有兼容的问题，毕竟各个数据库的SQL方言不一样。不过有一点需要注意的是，如果要直接使用原生SQL语句，在被query()所查询的映射类中，你必须保证语句所指代的列仍然被映射类所管理，比如接下来的例子：

>>> session.query(User).from_statement(
...           "SELECT * FROM users where name=:name").\
...           params(name='ed').all()
SELECT * FROM users where name=&#63;
('ed',)
 
[<User('ed','Ed Jones', 'f8s7ccs')>]

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我们还可以在query()中直接使用列名来指派我们想要的列而摆脱映射类的束缚：

>>> session.query("id", "name", "thenumber12").\
...     from_statement("SELECT id, name, 12 as "
...         "thenumber12 FROM users where name=:name").\
...         params(name='ed').all()
SELECT id, name, 12 as thenumber12 FROM users where name=&#63;
('ed',)
 
[(1, u'ed', 12)]

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3. 计数 (Counting)

对于Query来说，计数功能也有个单独的方法称为count()：

>>> session.query(User).filter(User.name.like('%ed')).count() 
SELECT count(*) AS count_1
FROM (SELECT users.id AS users_id,
        users.name AS users_name,
        users.fullname AS users_fullname,
        users.password AS users_password
FROM users
WHERE users.name LIKE &#63;) AS anon_1
('%ed',)
 
2

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count()方法被用于确定返回的结果集中有多少行，让我们观察一下产生的SQL语句，SQLAlchemy先是取出符合条件的所有行集合，然后再通过SELECT count(*)来统计有多少行。当然有点SQL知识的同学可能知道这条语句可以以更精简的方式写出来，比如SELECT count(*) FROM table，当然现代版本的SQLAlchemy不会去揣摩这样的想法。

假使我们要让查询语句更加精炼或者要明确要统计的列，我们可以通过表达式func.count()直接使用count函数，比如下面的例子介绍统计并返回每个唯一的用户名字：

>>> from sqlalchemy import func
>>> session.query(func.count(User.name), User.name).group_by(User.name).all() 
SELECT count(users.name) AS count_1, users.name AS users_name
FROM users GROUP BY users.name
()
 
[(1, u'ed'), (1, u'fred'), (1, u'mary'), (1, u'wendy')]

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对于刚才提到的简单SELECT count(*) FROM table语句，我们可以通过下面的例子来实现：

>>> session.query(func.count('*')).select_from(User).scalar()
SELECT count(&#63;) AS count_1
FROM users
('*',)
 
4

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当然如果我们直接统计User的主键，上面的语句可以更加简练，我们可以省去select_from()方法：

>>> session.query(func.count(User.id)).scalar() 
SELECT count(users.id) AS count_1
FROM users
()
 
4

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