Python使用scrapy抓取网站sitemap信息的方法

WBOY
Release: 2016-06-10 15:15:55
Original
1175 people have browsed it

本文实例讲述了Python使用scrapy抓取网站sitemap信息的方法。分享给大家供大家参考。具体如下:

import re
from scrapy.spider import BaseSpider
from scrapy import log
from scrapy.utils.response import body_or_str
from scrapy.http import Request
from scrapy.selector import HtmlXPathSelector
class SitemapSpider(BaseSpider):
 name = "SitemapSpider"
 start_urls = ["http://www.domain.com/sitemap.xml"]
 def parse(self, response):
  nodename = 'loc'
  text = body_or_str(response)
  r = re.compile(r"(<%s[\s>])(.*&#63;)(</%s>)"%(nodename,nodename),re.DOTALL)
  for match in r.finditer(text):
   url = match.group(2)
   yield Request(url, callback=self.parse_page)
 def parse_page(self, response):
    hxs = HtmlXPathSelector(response)
    #Mock Item
  blah = Item()
  #Do all your page parsing and selecting the elemtents you want
    blash.divText = hxs.select('//div/text()').extract()[0]
  yield blah
Copy after login

希望本文所述对大家的Python程序设计有所帮助。

Related labels:
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template