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初学Python函数的笔记整理

Jun 10, 2016 pm 03:16 PM
python function

 定义
返回单值

def my_abs(x):
  if x >= 0:
    return x
  else:
    return -x
 
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返回多值

返回多值就是返回一个tuple

import math
 
def move(x, y, step, angle=0):
  nx = x + step * math.cos(angle)
  ny = y - step * math.sin(angle)
  return nx, ny
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空函数

def nop():
  pass
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指定默认参数

必选参数在前,默认参数在后。默认参数需指向不可变对象(默认参数值在函数定义时被计算)

def power(x, n=2):
  s = 1
  while n > 0:
    n = n - 1
    s = s * x
  return s
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可变参数

def calc(*numbers):
  sum = 0
  for n in numbers:
    sum = sum + n * n
  return sum
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调用可变参数的函数方法

>>> calc(1, 2)
5
>>> calc()
0
>>> nums = [1, 2, 3]
>>> calc(*nums)
14
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关键字参数

def person(name, age, **kw):
  print 'name:', name, 'age:', age, 'other:', kw
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调用关键字参数的方法

>>> person('Michael', 30)
name: Michael age: 30 other: {}
>>> person('Bob', 35, city='Beijing')
name: Bob age: 35 other: {'city': 'Beijing'}
>>> person('Adam', 45, gender='M', job='Engineer')
name: Adam age: 45 other: {'gender': 'M', 'job': 'Engineer'}
>>> kw = {'city': 'Beijing', 'job': 'Engineer'}
>>> person('Jack', 24, **kw)
name: Jack age: 24 other: {'city': 'Beijing', 'job': 'Engineer'}
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注:

参数定义的顺序必须是:必选参数、默认参数、可变参数和关键字参数。
对于任意函数,都可以通过类似func(*args, **kw)的形式调用它,无论它的参数是如何定义的。

递归

如果一个函数在内部调用自身本身,这个函数就是递归函数。
尾递归

在函数返回的时候,调用自身本身,并且,return语句不能包含表达式。
高阶函数

  • 变量可以指向函数(函数可以赋值给一个变量)
  • 函数名也是变量(函数名可以赋值其他值)
  • 函数可以做为函数的参数(高阶函数)

map(func, list)

map()函数接收两个参数,一个是函数,一个是序列,map将传入的函数依次作用到序列的每个元素,并把结果作为新的list返回。

>>> def f(x):
...   return x * x
...
>>> map(f, [1, 2, 3, 4, 5, 6, 7, 8, 9])
[1, 4, 9, 16, 25, 36, 49, 64, 81]
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reduce(func_with_two_params, list)

reduce把一个函数作用在一个序列[x1, x2, x3…]上,这个函数必须接收两个参数,reduce把结果继续和序列的下一个元素做累积计算。

reduce(f, [x1, x2, x3, x4])
#相当于:
f(f(f(x1, x2), x3), x4)
 
>>> def add(x, y):
...   return x + y
...
>>> reduce(add, [1, 3, 5, 7, 9])
25
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filter(func_return_bool, list)

把传入的函数依次作用于每个元素,然后根据返回值是True还是False决定保留还是丢弃该元素。

def is_odd(n):
  return n % 2 == 1
 
filter(is_odd, [1, 2, 4, 5, 6, 9, 10, 15])
# 结果: [1, 5, 9, 15]
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sorted

对于两个元素x和y,如果认为x < y,则返回-1,如果认为x == y,则返回0,如果认为x > y,则返回1,

>>> sorted([36, 5, 12, 9, 21])
[5, 9, 12, 21, 36]
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高阶函数用法

def reversed_cmp(x, y):
  if x > y:
    return -1
  if x < y:
    return 1
  return 0
 
>>> sorted([36, 5, 12, 9, 21], reversed_cmp)
[36, 21, 12, 9, 5]
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函数做为返回值

def lazy_sum(*args):
  def sum():
    ax = 0
    for n in args:
      ax = ax + n
    return ax
  return sum
 
>>> f = lazy_sum(1, 3, 5, 7, 9)
>>> f
<function sum at 0x10452f668>
>>> f()
25
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注:每次调用lazy_sum()都会返回一个新的函数,即使传入相同的参数。
闭包

def count():
  fs = []
  for i in range(1, 4):
    def f():
       return i*i
    fs.append(f)
  return fs
 
f1, f2, f3 = count()
>>> f1()
9
>>> f2()
9
>>> f3()
9
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原因是调用count的时候循环已经执行,但是f()还没有执行,直到调用其时才执行。所以返回函数不要引用任何循环变量,或者后续会发生变化的变量。
匿名函数(lambda表达式)

等价于:

def f(x):
  return x * x
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关键字lambda表示匿名函数,冒号前面的x表示函数参数。
匿名函数做为返回值

def build(x, y):
  return lambda: x * x + y * y
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装饰器(@func)

在代码运行期间动态增加功能的方式,称之为“装饰器”(Decorator),本质上,decorator就是一个返回函数的高阶函数。

def log(func):
  def wrapper(*args, **kw):
    print 'call %s():' % func.__name__
    return func(*args, **kw)
  return wrapper
 
@log
def now():
  print '2013-12-25'
 
>>> now()
call now():
2013-12-25
 
#相当于执行:
 
now = log(now)
回到顶部
带参数的装饰器
 
def log(text):
  def decorator(func):
    def wrapper(*args, **kw):
      print '%s %s():' % (text, func.__name__)
      return func(*args, **kw)
    return wrapper
  return decorator
 
@log('execute')
def now():
  print '2013-12-25'
 
#执行结果
>>> now()
execute now():
2013-12-25
 
#相当于执行:
 
>>> now = log('execute')(now)
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剖析:首先执行log('execute'),返回的是decorator函数,再调用返回的函数,参数是now函数,返回值最终是wrapper函数。

__name__

由于函数的__name__已经改变,依赖于此的代码就会出错。因此使用functools.wraps。

import functools
 
def log(func):
  @functools.wraps(func)
  def wrapper(*args, **kw):
    print 'call %s():' % func.__name__
    return func(*args, **kw)
  return wrapper
 
#对于带参函数
 
import functools
 
def log(text):
  def decorator(func):
    @functools.wraps(func)
    def wrapper(*args, **kw):
      print '%s %s():' % (text, func.__name__)
      return func(*args, **kw)
    return wrapper
  return decorator
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偏函数(固定函数默认值)
>>> import functools
>>> int2 = functools.partial(int, base=2)
>>> int2('1000000')
64
>>> int2('1010101')
85
 
#相当于:
 
def int2(x, base=2):
  return int(x, base)
 
max2 = functools.partial(max, 10)
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相当于为max函数指定了第一个参数

max2(5, 6, 7)
 
#相当于:
 
max(10, 5, 6, 7)
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