PHP获取一年中每个星期的开始和结束日期的方法,php获取
PHP获取一年中每个星期的开始和结束日期的方法,php获取
本文实例讲述了PHP获取一年中每个星期的开始和结束日期的方法。分享给大家供大家参考。具体分析如下:
最近项目中需要做个提交周报的功能,需要知道指定周数的开始日期和结束日期,以便处理其他业务。以下是一段通过PHP来获取一年中的每星期的开始日期和结束日期的代码,与大家分享。
以下是一段通过PHP来获取一年中的每星期的开始日期和结束日期的代码。
function get_week($year) { $year_start = $year . "-01-01"; $year_end = $year . "-12-31"; $startday = strtotime($year_start); if (intval(date('N', $startday)) != '1') { $startday=strtotime("nextmonday",strtotime($year_start)); //获取年第一周的日期 } $year_mondy = date("Y-m-d", $startday);//获取年第一周的日期 $endday = strtotime($year_end); if (intval(date('W', $endday)) == '7') { $endday=strtotime("lastsunday",strtotime($year_end)); } $num = intval(date('W', $endday)); for ($i = 1; $i <= $num; $i++) { $j = $i -1; $start_date = date("Y-m-d", strtotime("$year_mondy $j week ")); $end_day = date("Y-m-d", strtotime("$start_date +6 day")); $week_array[$i] = array( str_replace("-",".",$start_date),str_replace("-",".",$end_day)); } return $week_array; }
函数get_week()通过传入参数$year年份,获取当年第一天和最后一天所在的周数,计算第一周的日期,通过循环获取每一周的第一天和最后一天的日期。最后返回是一个数组。
想得到指定周数的开始日期和结束日期,比如2011年第18周的开始日期和结束日期,代码如下:
$weeks = get_week(2011); echo '第18周开始日期:'.$weeks[18][0].''; echo '第18周结束日期:'.$weeks[18][1];
最后输出结果:
1. 第18周开始日期:2011.05.02 2. 第18周结束日期:2011.05.08
希望本文所述对大家的php程序设计有所帮助。

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