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php获取根域名方法汇总
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php获取根域名方法汇总

Jun 13, 2016 am 09:22 AM
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php获取根域名方法汇总

   如果你只简单获取当前访问你页面的域名,我们只需要使用php中的函数HTTP_HOST就可以搞定了,如果是提取url根域名是需要正则的,下面就来看看几个具体实例。

  如果是获取当前域名是非常的简单的:

  代码如下:

  

  //获取当前的域名:

  echo $_SERVER['SERVER_NAME'];

  //获取来源网址,即点击来到本页的上页网址

  echo $_SERVER["HTTP_REFERER"];

  $_SERVER['REQUEST_URI'];//获取当前域名的后缀

  $_SERVER['HTTP_HOST'];//获取当前域名

  dirname(__FILE__);//获取当前文件的物理路径

  dirname(__FILE__)."/../";//获取当前文件的上一级物理路径

  ?>

  例子1

  代码如下:

  function getUrlRoot($url){

  #添加头部和尾巴

  $url = $url . "/";

  #判断域名

  preg_match("/((\w*):\/\/)?\w*\.?([\w|-]*\.(com.cn|net.cn|gov.cn|org.cn|com|net|cn|org|asia|tel|mobi|me|tv|biz|cc|name|info))

  \//", $url, $ohurl);

  #判断IP

  if($ohurl[3] == ''){

  preg_match("/((\d+\.){3}\d+)\//", $url, $ohip);

  return $ohip[1];

  }

  return $ohurl[3];

  }

  例子2

  代码如下:

  /**

  * 取得根域名

  * @param type $domain 域名

  * @return string 返回根域名

  */

  function GetUrlToDomain($domain) {

  $re_domain = '';

  $domain_postfix_cn_array = array("com", "net", "org", "gov", "edu", "com.cn", "cn");

  $array_domain = explode(".", $domain);

  $array_num = count($array_domain) - 1;

  if ($array_domain[$array_num] == 'cn') {

  if (in_array($array_domain[$array_num - 1], $domain_postfix_cn_array)) {

  $re_domain = $array_domain[$array_num - 2] . "." . $array_domain[$array_num - 1] . "." . $array_domain[$array_num];

  } else {

  $re_domain = $array_domain[$array_num - 1] . "." . $array_domain[$array_num];

  }

  } else {

  $re_domain = $array_domain[$array_num - 1] . "." . $array_domain[$array_num];

  }

  return $re_domain;

  }

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