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php后台如何避免用户直接进入方法实例

WBOY
Release: 2016-06-13 09:31:41
Original
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1)创建BaseController控制器继承Controller(后台的一切操作要继承BaseController):

在BaseController里面添加:

复制代码 代码如下:


public function checkLogin() {

        if (Yii::app()->authority->isLogin() == Yii::app()->authority->getStatus('NOTLOGIN')) {
            $url = $this->createUrl('user/login');
            if (Yii::app()->request->isPostRequest && Yii::app()->request->isAjaxRequest) {
                echo json_encode(array('code' => -101, 'message' => '用户未登录。', 'callback' => 'window.location="' . $url . '";'));
            } else if (Yii::app()->request->isAjaxRequest) {
                echo '';
            } else {
                $this->redirect($url);
            }
            exit;
        }
        return true;
    }

在components目录下创建Authority.php文件:

复制代码 代码如下:



/**
 * 权限检查组件
 */
class Authority extends CComponent {
    private $NOTLOGIN = -1;
    private $FAILED = -2;
    private $PASS = 1;

    public function init() {

    }

    /**
     * 检查是否登陆
     * @return boolean 
     */
    function isLogin() {
        return isset(Yii::app()->session['user']) ? $this->PASS : $this->NOTLOGIN;
    }

  
    /**
     * 获取状态值
     * @param string $name
     * @return int 
     */
    public function getStatus($name){
        return $this->$name;
    }
}

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