php5.2以下版本无json_decode函数的解决方法
今天写代码的时候,需要用到json_decode函数,发现php5.2以前的版本没有集成这个函数,不过我们可以通过自定义函数实现。
复制代码 代码如下:
function json_decode2($json)
{
$comment = false;
$out = '$x=';
for ($i=0; $i
if (!$comment)
{
if (($json[$i] == '{') || ($json[$i] == '[')) $out .= ' array(';
else if (($json[$i] == '}') || ($json[$i] == ']')) $out .= ')';
else if ($json[$i] == ':') $out .= '=>';
else $out .= $json[$i];
}
else $out .= $json[$i];
if ($json[$i] == '"' && $json[($i-1)]!="\\") $comment = !$comment;
}
eval($out . ';');
return $x;
}
不过这个返回的是Array
要返回object 则要用到 service_json类了

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