Home > Backend Development > PHP Tutorial > mysql_fetch_row(): supplied argument is not a valid MySQL result resource,何人能解?该如何解决

mysql_fetch_row(): supplied argument is not a valid MySQL result resource,何人能解?该如何解决

WBOY
Release: 2016-06-13 09:59:42
Original
986 people have browsed it

mysql_fetch_row(): supplied argument is not a valid MySQL result resource,何人能解?
代码如下:

/*
 * Created on 2012-1-1
 *
 * To change the template for this generated file go to
 * Window - Preferences - PHPeclipse - PHP - Code Templates
 */
 $conn = mysql_connect("localhost","root","") or die ("连接出错");
 mysql_select_db("dongxinb",$conn);

 $sql="SELECT * FROM 'word'";
 $query=mysql_query($sql,$conn);
 $row=mysql_fetch_array($query);
 echo $row[name];
?>

其中name为dongxinb数据库word表的字段。
错误信息:Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in D:\wamp\www\word\1.php on line 13

其中INSERT能正常插入。




------解决方案--------------------
SQL 错了

修改成
$sql="SELECT * FROM word";
------解决方案--------------------

PHP code
<?php /* * Created on 2012-1-1 To change the template for this generated file go to * Window - Preferences - PHPeclipse - PHP - Code Templates */include ("conn.php");?>
Copy after login
html;}?>
姓名:{$row['name']}
Message:{$row['words']} 更新时间:{$row['date']}
Related labels:
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template