页面抓取!该如何处理
页面抓取!
我想要抓取http://www.56110.cn/goods/list_p1.html?goodtype=1这个页面下的货运信息,如何把每条信息中的详细信息都抓取到(就是查看里面的信息),帮忙看看,谢谢!
------解决方案--------------------
- PHP code
<?php $str = file_get_contents("http://www.56110.cn/goods/list_p1.html?goodtype=1");preg_match_all("/\<a\s+href\=\'(.*?)\'.*?\>.*?\/",$str,$match);print_r($match[1]);echo "<br>";foreach ($match[1] as $val){ $url= 'http://www.56110.cn'.$val; $str = file_get_contents($url); echo $str; break;}?><br><font color="#e78608">------解决方案--------------------</font><br>

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