Home > Backend Development > PHP Tutorial > mysql_fetch_array(): supplied argument is not a valid MySQL result resource,该怎么解决

mysql_fetch_array(): supplied argument is not a valid MySQL result resource,该怎么解决

WBOY
Release: 2016-06-13 10:02:04
Original
924 people have browsed it

mysql_fetch_array(): supplied argument is not a valid MySQL result resource
mysql_connect("localhost","root","1"); 
$query="select id from computer where user ='test2'";
$result=mysql_query($query);

echo "test2 使用了
";
while($row = mysql_fetch_array($result))
{
echo $row['id']."开始时间".$row[starttime]."
";
}
  Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in D:\myapacheweb\test\self_info.php on line 7


------解决方案--------------------
没有选择数据库
mysql_select_db(表名)
------解决方案--------------------
mysql_select_db

Related labels:
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template