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PHP构造函数解决思路

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Release： 2016-06-13 10:08:00
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PHP构造函数
现在在写一个类，遇到这样一个问题，如果在构造函数中发现该对象不符合构造条件，如何让对象构造停止，并返回false通知外围对象。。。
在线等。。。

------解决方案--------------------
请码点马贴上来啊
------解决方案--------------------
你可能需要重载 new，不过 php 并不支持重载

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false new php
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