这条语句为什么没有执行?解决思路

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Release: 2016-06-13 10:09:23
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这条语句为什么没有执行?

PHP code
<!--Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/-->$query=mysql_query("insert into yc_jiage(yc_jiage,add_date,yc_name,yc_id) values ($_price1,$_date1,'毛衣'`,null)");
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插入语句,没有任何提示,但数据就是没有插入!
PHP code
<!--Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/-->echo $_date1
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倒是能正常显示,说明变量没有问题!

$_price1和 $_date1 都是POST接收来的变量!
表中 yc_id 字段,是自动增长的

------解决方案--------------------
mysql_query("insert into yc_jiage(yc_jiage,add_date,yc_name) values ($_price1,$_date1,'毛衣')");

试试看?
------解决方案--------------------
$query=mysql_query("insert into yc_jiage(yc_jiage,add_date,yc_name,yc_id) values ('$_price1','$_date1','毛衣'`,null)") or die(mysql_error()); 

这样试试。错了的话有提示。
------解决方案--------------------
$query=mysql_query("insert into yc_jiage(yc_jiage,add_date,yc_name,yc_id) values ('$_price1','$_date1','毛衣',null)");
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