找出重复数据来,函数改写
数据库里这样子,
id wc we
1 q 3
2 a 0
3 q 3
4 b 1
5 b 1
6 q 2
7 q 2
8 g 3
我要得到:变成
id wc we
1 q 3-1/2
3 q 3-2/2
4 b 1-1/2
5 b 1-2/2
6 q 2-1/2
7 q 2-2/2
------解决方案--------------------
蛋痛了数个小时终于写好了,我擦!这个时候十分想念怪署黍啊...感觉代码写得太恶心了。
得到结果 循环数组拼装成 SQL update 数据库。搞成函数什么的就自己劳动啦,代码看不懂也莫问我,咔咔,太费脑子了.
Array
(
[0] => 1 23 234
[1] => 2 24 235-1/2
[2] => 3 24 235-2/2
[3] => 4 25 235-1/2
[4] => 5 25 235-2/2
[5] => 6 37 456-1/2
[6] => 7 37 456-2/2
)
$array = array('1 23 234', '2 24 235', '3 24 235', '4 25 235', '5 25 235', '6 37 456', '7 37 456');$newArray = array();foreach ($array as $value) { preg_match('/^[0-9]+\s([0-9]+\s[0-9]+$)/', $value, $mArray); $newArray[] = $mArray[1];}$countArray = array_count_values($newArray);$fixArray = array();$i = 1;foreach ($newArray as $newkey => &$value) { $newArrayKey = array(); if (array_key_exists($value, array_flip($newArray))) { $newArrayKey = array_keys($newArray, $value); if (count($newArrayKey) !== 1) { $tmp = array_search($newkey, $newArrayKey); $tmp = intval($tmp) + 1; $fixArray[] = $i . ' ' . $value . '-' . $tmp . '/' . $countArray[$value]; } else { $fixArray[] = $i . ' ' . $value; } $i++; }}print_r($fixArray);<br><font color="#e78608">------解决方案--------------------</font><br>妞妞,哪有事情做到一半的到底。起码也要注释解释一下吧。。<br><br>话说大版已好久没现身了。挺想念的。。<div class="clear"> </div>