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函数形参解决方法

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Release： 2016-06-13 10:12:24
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函数形参
函数参数类型为类时，指定类型与不指定类型有什么区别？比如有一个con类，function(con $lk);和function($lk);有和区别？

------解决方案--------------------
指定了 就 必须为该类型
不指定 就不必须为该类型.....

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