在一个form表单中，存在多个select，递交到后台文件后，怎么获取到这几个select被选中的值？
在一个form表单中，存在多个select，递交到后台文件后，如何获取到这几个select被选中的值？？
在一个form表单中，存在多个select，递交到add.php文件后，如何获取到这两个select被选中的值？？
------解决方案--------------------
$_POST['selteaid'];
$_POST['selclaid'];
------解决方案--------------------
form表单中action的参数有用吗？
如果有用：
if(isset($_GET['addTeahcer'])){
echo "下拉菜单1-->>";print_r($_POST['selteaid']);echo "
";
echo "下拉菜单1-->>";print_r($_POST['selclaid']);echo "
";
}
前提是你的前端页面中的下拉菜单有被选择的值:
------解决方案--------------------
不同的select的name属性设置不一样，然后用$_POST就可以获得了
------解决方案--------------------
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