Table of Contents
如何在 Golang 中用正则表达式检测 URL?
语法
模式
实战案例
Home Backend Development Golang How to detect URL with regular expression in Golang?

How to detect URL with regular expression in Golang?

May 31, 2024 am 10:32 AM
regular expression url

使用正则表达式在 Golang 中检测 URL 的步骤如下:使用 regexp.MustCompile(pattern) 编译正则表达式模式。模式需匹配协议、主机名、端口(可选)、路径(可选)和查询参数(可选)。使用 regexp.MatchString(pattern, url) 检测 URL 是否匹配模式。

如何在 Golang 中用正则表达式检测 URL?

如何在 Golang 中用正则表达式检测 URL?

正则表达式是一种强大的工具,用于在文本中查找特定模式。在 Golang 中,我们可以使用正则表达式来验证 URL 是否有效。

语法

Golang 中使用正则表达式的语法如下:

regexp.MustCompile(pattern)
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其中,pattern 是要匹配的正则表达式模式。

模式

对于 URL,我们需要一个模式来匹配以下元素:

  • 协议(例如 https:// 或 http://)
  • 主机名
  • 端口(可选)
  • 路径(可选)
  • 查询参数(可选)

我们可以使用下面的正则表达式模式:

^(https?:\/\/)?([\da-z\.-]+)\.([a-z\.]{2,6})([\/\w \.-]*)*\/?$
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实战案例

下面是一个使用正则表达式检测 URL 的实战案例:

package main

import (
    "fmt"
    "regexp"
)

func main() {
    // 要检测的 URL
    urls := []string{
        "https://www.google.com",
        "http://example.com",
        "ftp://ftp.example.com",
        "example.com",
        "127.0.0.1",
        "google.com",
    }

    // 正则表达式模式
    pattern := "^(https?:\\/\\/)?([\\da-z\\.-]+)\\.([a-z\\.]{2,6})([\\/\\w \\.-]*)*\\/?$"

    for _, url := range urls {
        result, err := regexp.MatchString(pattern, url)
        if err != nil {
            fmt.Println("Error:", err)
        }

        if result {
            fmt.Println("Valid URL:", url)
        } else {
            fmt.Println("Invalid URL:", url)
        }
    }
}
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输出:

Valid URL: https://www.google.com
Valid URL: http://example.com
Invalid URL: ftp://ftp.example.com
Invalid URL: example.com
Invalid URL: 127.0.0.1
Invalid URL: google.com
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