How to avoid generating duplicate random numbers in Golang?

Method to avoid generating repeated random numbers in Golang: Create a new random number generator rand.New(rand.Source). Use rand.NewSource(time.Now().UnixNano()) as the entropy source. Use rand.Intn(n) to generate random integers.

#How to avoid generating repeated random numbers in Golang?

In Golang, generating random numbers requires using the math/rand package. Use the rand.Intn(n) function to generate a random integer in the range [0, n-1], where n is a positive integer. However, rand.Intn(n) may generate repeated random numbers in a concurrent environment.

To solve this problem, you can use the rand.New(rand.Source) function to create a new random number generator and use io.Reader as entropy source. In most cases, using rand.NewSource(time.Now().UnixNano()) as the entropy source will suffice.

The following is a sample code that shows how to use rand.NewSource to avoid generating duplicate random numbers:

package main

import (
    "math/rand"
    "time"
)

func main() {
    // 创建一个新的随机数生成器，并使用时间戳作为熵源
    r := rand.New(rand.NewSource(time.Now().UnixNano()))

    // 生成 10 个随机整数
    for i := 0; i < 10; i++ {
        result := r.Intn(100)
        println(result)
    }
}

By using rand.NewSource and time.Now().UnixNano() serve as a source of entropy to generate unique and unpredictable random numbers.

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