How to generate random hexadecimal numbers in Golang?

How to generate random hexadecimal numbers in Go: introduce and initialize the math/rand package. Generate a random integer via rand.Intn(16777216). Use fmt.Sprintf("%x", ) to convert an integer to a hexadecimal string.

How to generate random hexadecimal numbers in Go?

Generating random hexadecimal numbers in Go is very easy. You can use the built-in math/rand package. The following is a sample code that demonstrates how to generate a random 6-digit hexadecimal number:

package main

import (
    "fmt"
    "math/rand"
    "time"
)

func main() {
    // 初始化随机数生成器
    rand.Seed(time.Now().UnixNano())

    // 生成一个随机 6 位十六进制数
    hexValue := fmt.Sprintf("%x", rand.Intn(16777216))

    // 打印随机十六进制数
    fmt.Println("随机十六进制数：", hexValue)
}

Practical Case

The above sample code can be used to generate random hexadecimal numbers for various needs in several applications. For example, it can be used to generate unique IDs, cryptographic tokens, or other scenarios that require random hex strings.

The following are some practical application cases:

• Generate unique ID: You can use random hexadecimal numbers to generate unique IDs, such as order numbers or Customer reference number.
• Create cryptographic tokens: Random hexadecimal numbers can be used to create secure cryptographic tokens to protect sensitive information.
• Generate verification code: Hexadecimal string can be used to generate verification code to prevent robot attacks.

These are just some of the potential uses for random hexadecimal numbers in Go. With a little creativity and imagination, you can find more interesting ways to use them.

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