How to generate random elements from list in Golang?

How to generate random elements of a list in Golang: use rand.Intn(len(list)) to generate a random integer within the length range of the list; use the integer as an index to get the corresponding element from the list.

#How to generate random elements from a list in Golang?

In Golang, you can use the built-in rand package to generate a random integer in a range, and then use this integer to index the list and get a random element.

The following is the code on how to implement it:

package main

import (
    "fmt"
    "math/rand"
    "time"
)

func main() {
    // 创建一个元素列表
    list := []string{"a", "b", "c", "d", "e"}

    // 设置随机种子（通常使用当前时间作为种子）
    rand.Seed(time.Now().UnixNano())

    // 生成一个范围内的随机整数，范围为 [0, len(list)-1]
    n := rand.Intn(len(list))

    // 使用随机整数作为索引，从列表中获取随机元素
    randomElement := list[n]

    fmt.Println(randomElement)
}

Practical case:

The following is an example showing how to use the above code in a program to generate a Random number:

package main

import (
    "fmt"
    "math/rand"
    "time"
)

func main() {
    numbers := []int{1, 2, 3, 4, 5}

    // 生成一个随机索引
    randomIndex := rand.Intn(len(numbers))

    // 获取随机数字
    randomNumber := numbers[randomIndex]

    fmt.Println(randomNumber)
}

Running this program will output a number randomly selected from the list.

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