javascript空白验证还是不行解决方案
javascript空白验证还是不行
这是个餐馆网站,菜单可以选点的菜的数量,然后放进购物车里面。
- PHP code
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之前发的帖子问了,但是我问错了,form是在循环里面,所以不能用getElementById来判断。在此感谢一下T5500对我帮助。
每个form里面只有一个input type=text 现在就是在每个form提交之前,怎么判断每个text不能为空或者为0 ??
------解决方案--------------------
onsubmit='return dosubmit();'
改为
onsubmit='return dosubmit(this);'
js
- JScript code
function dosubmit(fmt) { if(fmt.textbox_qty.value == '') { fmt.textbox_qty.focus(); alert('不能为空'); return false; } return true;}<br><font color="#e78608">------解决方案--------------------</font><br>function isEmpty()<br>{<br> function isEmpty() {<br>这里看到函数命名两次。是手误还是什么?<div class="clear"> </div>

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php提交表单通过后,弹出的对话框怎样在当前页弹出php提交表单通过后,弹出的对话框怎样在当前页弹出而不是在空白页弹出?想实现这样的效果:而不是空白页弹出:------解决方案--------------------如果你的验证用PHP在后端,那么就用Ajax;仅供参考:HTML code

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