Home Backend Development PHP Tutorial javascript空白验证还是不行解决方案

javascript空白验证还是不行解决方案

Jun 13, 2016 am 10:20 AM
div gt input lt name

javascript空白验证还是不行
这是个餐馆网站,菜单可以选点的菜的数量,然后放进购物车里面。

PHP code
<!--Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/-->while(...){echo "
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"; echo "
$dish_name
Description: $dish_descr
  Qty:
"; echo ""; echo "
";}

之前发的帖子问了,但是我问错了,form是在循环里面,所以不能用getElementById来判断。在此感谢一下T5500对我帮助。
每个form里面只有一个input type=text 现在就是在每个form提交之前,怎么判断每个text不能为空或者为0 ??


------解决方案--------------------
onsubmit='return dosubmit();'
改为
onsubmit='return dosubmit(this);'

js
JScript code
function dosubmit(fmt) {  if(fmt.textbox_qty.value == '') {    fmt.textbox_qty.focus();    alert('不能为空');    return false;  }  return true;}<br><font color="#e78608">------解决方案--------------------</font><br>function isEmpty()<br>{<br>   function isEmpty() {<br>这里看到函数命名两次。是手误还是什么?<div class="clear">
                 
              
              
        
            </div>
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php提交表单通过后,弹出的对话框怎样在当前页弹出,该如何解决 php提交表单通过后,弹出的对话框怎样在当前页弹出,该如何解决 Jun 13, 2016 am 10:23 AM

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