How is type assertion implemented in golang functions?

WBOY
Release: 2024-06-06 10:26:34
Original
983 people have browsed it

Type assertion is implemented through the following steps: The compiler generates a runtime.type structure containing type information and method tables. When type-asserting a value, the compiler checks whether its runtime.type structure matches the target type. When the match succeeds, the type assertion succeeds, ok is true, and the value is extracted. When the match fails, the type assertion fails, ok is false, and value is set to nil.

How is type assertion implemented in golang functions?

#How are type assertions implemented in Go functions?

Type assertions allow us to check whether a value belongs to a certain type and extract its value. It is implemented using the interface{} and type keywords.

Syntax

The syntax of type assertion is as follows:

value, ok := value.(type)
Copy after login

Where:

  • value Is the value to be type-asserted.
  • type is the type to check.
  • ok is a Boolean value that tells us whether the type assertion is successful. When ok is true, value belongs to the specified type and we can access its actual value in value. When ok is false, the type assertion fails and value is nil.

Implementation

Under the hood, type assertions are implemented through the following steps:

  1. The compiler generates a runtime .type structure, which contains type information and method tables.
  2. When making a type assertion on a value, the compiler checks whether the value's runtime.type structure matches the target type's runtime.type structure.
  3. If matched, the type assertion succeeds, ok is true, and the actual value of the value is stored in value.
  4. If there is no match, the type assertion fails, ok is false, and value is set to nil.

Practical case

The following is a practical example of using type assertions:

package main

import "fmt"

func main() {
    var value interface{} = 42

    if i, ok := value.(int); ok {
        fmt.Println("Value is of type int and its value is:", i)
    } else {
        fmt.Println("Value is not of type int")
    }
}
Copy after login

Result:

Value is of type int and its value is: 42
Copy after login

Note:

  • Type assertions can only be used to check specific types, not interface types.
  • If a type assertion fails, value will be set to nil, even if the original value was not nil.

The above is the detailed content of How is type assertion implemented in golang functions?. For more information, please follow other related articles on the PHP Chinese website!

Related labels:
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template
About us Disclaimer Sitemap
php.cn:Public welfare online PHP training,Help PHP learners grow quickly!