1823. Find the Winner of the Circular Game
Medium
There are n friends that are playing a game. The friends are sitting in a circle and are numbered from 1 to n in clockwise order. More formally, moving clockwise from the ith friend brings you to the (i+1)th friend for 1 <= i < n, and moving clockwise from the nth friend brings you to the 1st friend.
The rules of the game are as follows:
-
Start at the 1st friend.
- Count the next k friends in the clockwise direction including the friend you started at. The counting wraps around the circle and may count some friends more than once.
- The last friend you counted leaves the circle and loses the game.
- If there is still more than one friend in the circle, go back to step 2 starting from the friend immediately clockwise of the friend who just lost and repeat.
- Else, the last friend in the circle wins the game.
Given the number of friends, n, and an integer k, return the winner of the game.
Example 1:
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Input: n = 5, k = 2
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Output: 3
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Explanation: Here are the steps of the game:
- Start at friend 1.
- Count 2 friends clockwise, which are friends 1 and 2.
- Friend 2 leaves the circle. Next start is friend 3.
- Count 2 friends clockwise, which are friends 3 and 4.
- Friend 4 leaves the circle. Next start is friend 5.
- Count 2 friends clockwise, which are friends 5 and 1.
- Friend 1 leaves the circle. Next start is friend 3.
- Count 2 friends clockwise, which are friends 3 and 5.
- Friend 5 leaves the circle. Only friend 3 is left, so they are the winner.
Example 2:
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Input: n = 6, k = 5
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Output: 1
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Explanation: The friends leave in this order: 5, 4, 6, 2, 3. The winner is friend 1.
Constraints:
Follow up:
Could you solve this problem in linear time with constant space?
Solution:
class Solution {
/**
* @param Integer $n
* @param Integer $k
* @return Integer
*/
function findTheWinner($n, $k) {
$winner = 0;
for ($i = 1; $i <= $n; $i++) {
$winner = ($winner + $k) % $i;
}
return $winner + 1; // +1 because array index starts from 0
}
}
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