Swapping two numbers is a common task in programming interviews, and there are various ways to achieve this. One interesting method is to swap two numbers without using a temporary variable. This technique is not only clever but also helps in understanding arithmetic operations in Java. In this article, we will explore this method and provide a sample code implementation.
The idea behind swapping two numbers without a temporary variable is based on basic arithmetic operations. The core idea is to use addition and subtraction to perform the swap. Here's how it works:
Here's a simple Java program that demonstrates this method:
package basics; public class SwapTwoNumbersWithoutTemp { private void swapNumbers(int a, int b) { a = a + b; // Step 1: a becomes the sum of a and b b = a - b; // Step 2: b becomes the original value of a a = a - b; // Step 3: a becomes the original value of b System.out.println("a = " + a + " b = " + b); } public static void main(String[] args) { SwapTwoNumbersWithoutTemp swap = new SwapTwoNumbersWithoutTemp(); swap.swapNumbers(5, 6); } }
Swapping two numbers without a temporary variable is an efficient and clever technique often asked in interviews. This method not only saves memory but also showcases your understanding of basic arithmetic operations. It can be a great addition to your coding toolbox, especially for interview preparation.
Feel free to experiment with this code and test different pairs of numbers to see how the method performs!
Java Fundamentals: Data Types
Check out my series on Array Interview Essentials for more tips and insights into Java programming.
Happy Coding!
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