Home > Backend Development > C++ > body text

Quick Zig and C String Conversion Conundrums

Linda Hamilton
Release: 2024-10-14 08:07:31
Original
395 people have browsed it

Quick Zig and C String Conversion Conundrums

Intro

My background is mostly in C and as I am still new to zig some of the type conversions needed for C and Zig to talk were not crystal clear at the beginning. Now I understand them and I'll give a quick rundown to hopefully help anyone else that needs it.

C String types

Let's start off with what a C string type is in Zig. There are 2 recommended1 ways of denoting a C string.

// Sentinel slice of unknown amount
[*:0]const u8
// Slice of unknown amount
[*]const u8
Copy after login

If you can expect the string to be null-terminated you want the first option which can be converted into a Zig slice with the std.mem.span function. Otherwise, you'll want the second option with you usually requiring a length parameter passed into your exported function so you can get a slice-by-length.

Examples:

export pub fn test_c_string(str: [*:0]const u8) void {
    const local_slice: []const u8 = std.mem.span(str);
    // rest of function
}
Copy after login
export pub fn test_c_string(str: [*]const u8, len: usize) void {
    const local_slice: []const u8 = str[0..len];
    // rest of the function
}
Copy after login

That's really all you need to know for your C string needs. The rest of Zig's strings can convert between Zig slice/array types fairly easily without much intervention.

One type that confused me at first was array sentinel types (i.e. [5:0]const u8) because I assumed it was similar to [*:0]const u8 but the difference is the comptime length (i.e. 5) which turns this slice into a known length so Zig can do it's slice conversions between similar types easily.

  1. You can also do [*c] to signify a C pointer but it is noted this should only be used in autogenerated code.

The above is the detailed content of Quick Zig and C String Conversion Conundrums. For more information, please follow other related articles on the PHP Chinese website!

source:dev.to
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Articles by Author
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template