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How to Upload a File Using file_get_contents and HTTP Stream Context?

Barbara Streisand
Release: 2024-10-18 11:59:03
Original
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How to Upload a File Using file_get_contents and HTTP Stream Context?

Uploading a File with file_get_contents and HTTP Stream Context

Unlike CURL, file_get_contents() can also be utilized to upload files to remote web servers using the HTTP stream context. To achieve this, follow these steps:

1. Define the Boundary:

Start by defining a boundary that will separate each part of the multipart Content-Type. Choose a string that doesn't exist within the content body.

<code class="php">define('MULTIPART_BOUNDARY', '--------------------------'.microtime(true));</code>
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2. Set the Content-Type Header:

Send the boundary in the Content-Type header to indicate the expected delimiter.

<code class="php">$header = 'Content-Type: multipart/form-data; boundary='.MULTIPART_BOUNDARY;</code>
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3. Define the Form Field Name:

Specify the name of the form field to which the file will be uploaded.

<code class="php">// equivalent to <input type="file" name="uploaded_file"/>
define('FORM_FIELD', 'uploaded_file'); </code>
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4. Build the Content Body:

Construct the content body according to the HTTP specification and the header sent. Include the necessary headers and file content.

<code class="php">$filename = "/path/to/uploaded/file.zip";
$file_contents = file_get_contents($filename);    

$content =  "--".MULTIPART_BOUNDARY."\r\n".
            "Content-Disposition: form-data; name=\"".FORM_FIELD."\"; filename=\"".basename($filename)."\"\r\n".
            "Content-Type: application/zip\r\n\r\n".
            $file_contents."\r\n";

// add POST fields
$content .= "--".MULTIPART_BOUNDARY."\r\n".
            "Content-Disposition: form-data; name=\"foo\"\r\n\r\n".
            "bar\r\n";

// end of request
$content .= "--".MULTIPART_BOUNDARY."--\r\n";</code>
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5. Create the Context:

Build the stream context with the necessary HTTP parameters.

<code class="php">$context = stream_context_create(array(
    'http' =&gt; array(
          'method' =&gt; 'POST',
          'header' =&gt; $header,
          'content' =&gt; $content,
    )
));</code>
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6. Execute the Request:

Upload the file using file_get_contents() with the context.

<code class="php">file_get_contents('http://url/to/upload/handler', false, $context);</code>
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Remember, binary files do not need to be encoded before transmission. HTTP can handle them directly.

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source:php
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