How to Efficiently Check List Subset Membership in Performance-Critical Scenarios?

Mary-Kate Olsen
Release: 2024-10-18 13:55:30
Original
663 people have browsed it

How to Efficiently Check List Subset Membership in Performance-Critical Scenarios?

Verifying List Subset Membership for Performance-Critical Scenarios

Given two lists, determining whether one is a subset of the other is a common operation. To achieve optimal performance, selecting the most efficient approach is essential.

One method involves intersecting the sets derived from the lists and checking if the result is equal to one set. However, given the number of datasets involved, a more performant solution is necessary.

When one list is static and the other is a dynamic dictionary from which keys are extracted, an alternative approach is recommended. Consider the following solution:

<code class="python">def is_subset(lookup_table, dynamic_list):
    # Convert lookup table to a set for efficient lookups
    lookup_set = set(lookup_table)
    
    # Convert dynamic list to a set for faster comparisons
    dynamic_set = set(dynamic_list.keys())
    
    # Check if the dynamic list's set is a subset of the lookup table's set
    return dynamic_set <= lookup_set
Copy after login

By converting the static lookup table and dynamic list to sets, the lookup operations are significantly faster. Additionally, the use of the <= operator to compare sets is highly efficient.

Examples:

<code class="python">>>> lookup_table = [1, 3, 5]
>>> dynamic_list = [1, 3, 5, 8]
>>> is_subset(lookup_table, dynamic_list)
True

>>> lookup_table = ['yes', 'no', 'hmm']
>>> dynamic_list = ['sorry', 'no', 'hmm']
>>> is_subset(lookup_table, dynamic_list)
False</code>
Copy after login

The above is the detailed content of How to Efficiently Check List Subset Membership in Performance-Critical Scenarios?. For more information, please follow other related articles on the PHP Chinese website!

source:php
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Articles by Author
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template