Home > Web Front-end > JS Tutorial > How to Ensure Ajax Calls Display Results in ASP.NET MVC Controllers?

How to Ensure Ajax Calls Display Results in ASP.NET MVC Controllers?

Mary-Kate Olsen
Release: 2024-10-18 22:17:02
Original
374 people have browsed it

How to Ensure Ajax Calls Display Results in ASP.NET MVC Controllers?

Making Ajax Calls to Controllers in ASP.NET MVC

When using ASP.NET MVC to perform Ajax operations, a common issue arises when expecting an alert to display the result from a controller method. While the controller is returning the desired data, the alert may not fire.

Controller Modification

To resolve this issue, the controller method that handles the Ajax call should be modified as follows:

public class AjaxTestController : Controller
{
    //
    // GET: /AjaxTest/
    public ActionResult FirstAjax()
    {
        return View();
    }

    [HttpPost]
    public ActionResult FirstAjax(string a) // Added a parameter "a"
    {
        return Json("chamara", JsonRequestBehavior.AllowGet);
    }
}
Copy after login

Request Data Removal

In the Ajax operation, the data attribute should be removed as no parameters are being sent to the server. This attribute is relevant when posting data to the server.

$.ajax({
    type: "POST",
    url: '@Url.Action("FirstAjax", "AjaxTest")',
    contentType: "application/json; charset=utf-8",
    dataType: "json",
    success: successFunc,
    error: errorFunc
});
Copy after login

Error Resolution

If the error persists, an alternative solution is to use Razor and @Url.Action instead of a static string:

$.ajax({
    url: '@Url.Action("FirstAjax", "AjaxTest")',
    contentType: "application/json; charset=utf-8",
    dataType: "json",
    success: successFunc,
    error: errorFunc
});
Copy after login

By following these steps, developers can ensure that Ajax calls in ASP.NET MVC applications are functioning correctly and producing the desired results.

The above is the detailed content of How to Ensure Ajax Calls Display Results in ASP.NET MVC Controllers?. For more information, please follow other related articles on the PHP Chinese website!

source:php
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Articles by Author
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template