How to Run a Slave Script Asynchronously in Python using Non-Blocking Process Invocation?

Non-blocking subprocess.call

In this scenario, you intend to invoke a slave script (slave.py) from a parent script (main.py) asynchronously. Specifically, you want slave.py to run independently of main.py after receiving arguments from main.py upon its initial execution.

To achieve non-blocking behavior, you should employ subprocess.Popen instead of subprocess.call. The key difference is that subprocess.call waits for the command to complete before proceeding, while subprocess.Popen does not.

Here's an example using subprocess.Popen:

import subprocess

# Pass the arguments from main.py to slave.py
arguments = ['python', 'slave.py'] + sys.argv[1:]

# Launch slave.py as a non-blocking process
process = subprocess.Popen(arguments)

Now, main.py can continue its execution while slave.py runs independently.

Additional Notes:

• Do not use a list to pass in the arguments if you're using shell=True.
• Alternatively, you can leverage asyncio for coroutine-based parallelism. See the example provided in the original answer for details.

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