Comparing dataframes to identify differences is essential for data analysis. In this problem, we are given two dataframes, df1 and df2, and need to find rows present in df2 but absent in df1.
Direct comparison using operators like != can lead to errors if the dataframes have different structures. A better approach is to concatenate the dataframes, reset their indices, and then compare them. Using df1 == df2 will result in a boolean matrix where True indicates rows present in both dataframes and False indicates differences.
Next, we can perform a group-by operation on the concatenated dataframe to identify unique rows. The goal is to find rows that occur only once in the dataframe. We can achieve this by checking the length of the groups; rows with a length of 1 represent unique records.
Finally, we can use the identified unique row indices to filter the dataframe. This will provide us with the rows in df2 that are not present in df1.
For instance, considering the example dataframes provided:
<code class="python">import pandas as pd df1 = ... df2 = ... # Concatenate dataframes df = pd.concat([df1, df2]) df = df.reset_index(drop=True) # Group by unique values df_gpby = df.groupby(list(df.columns)) # Get unique row indices idx = [x[0] for x in df_gpby.groups.values() if len(x) == 1] # Filter dataframe result = df.reindex(idx)</code>
The result dataframe will contain the rows in df2 that are not present in df1.
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