How to Compare Arrays of Objects in JavaScript: A Comprehensive Guide

Comparing Arrays of Objects in JavaScript: A Comprehensive Guide

Introduction:
In JavaScript coding, there often arises a need to compare arrays of objects. However, the objects may possess varying properties with missing values, complicating the comparison process.

Brute Force Approach:
One straightforward method is to iterate through each array and compare the values of the eight properties individually. However, this can become tedious and inefficient.

An Elegant Solution:

1. Count Property Comparison:
To overcome these challenges, you can utilize the following steps:

• Count the number of properties in both objects. If they differ, the objects are not equal.
• For each property, compare its values in both objects. If any of these values vary, the objects are not equal.

2. Object.keys() and Every() Methods:
Implementing this technique in JavaScript is straightforward using the Object.keys() and every() functions:

<code class="javascript">const objectsEqual = (o1, o2) =>
    Object.keys(o1).length === Object.keys(o2).length
        && Object.keys(o1).every(p => o1[p] === o2[p]);</code>

Example Usage:

<code class="javascript">const obj1 = { name: 'John', age: 33};
const obj2 = { age: 33, name: 'John' };
const obj3 = { name: 'John', age: 45 };

console.log(objectsEqual(obj1, obj2)); // true
console.log(objectsEqual(obj1, obj3)); // false</code>

This method ensures reliable comparison of arrays of objects, regardless of the property count or missing values.

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