How to Accurately Compare Object Arrays in JavaScript While Handling Missing Property Values?

Checking Similarity in Object Arrays in JavaScript

Comparing arrays of objects in JavaScript presents a challenge due to the dynamic nature of objects and the possibility of missing property values. While brute force methods may suffice, it is worthwhile exploring more elegant solutions.

One approach involves ensuring that the count of properties matches across the objects. Subsequently, each property value can be compared for equality. The following code demonstrates this approach:

<code class="js">const objectsEqual = (o1, o2) =>
    Object.keys(o1).length === Object.keys(o2).length
        && Object.keys(o1).every(p => o1[p] === o2[p]);</code>

To illustrate, consider the following objects:

<code class="js">const obj1 = { name: 'John', age: 33};
const obj2 = { age: 33, name: 'John' };
const obj3 = { name: 'John', age: 45 };</code>

When evaluated, the code outputs:

<code class="js">console.log(objectsEqual(obj1, obj2)); // true
console.log(objectsEqual(obj1, obj3)); // false</code>

This approach effectively compares object arrays, accounting for missing property values and ensuring accurate results.

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