In his book "Accelerated C ," Koenig introduces the concept of using the ' ' operator to concatenate string literals and objects. While this may seem straightforward, there are subtle nuances that can lead to unexpected results.
Consider the following two examples:
<code class="cpp">const string hello = "Hello"; const string message = hello + ",world" + "!";</code>
<code class="cpp">const string exclam = "!"; const string message = "Hello" + ",world" + exclam;</code>
The first example successfully concatenates the three strings. However, the second example fails.
To understand the discrepancy, we must consider the associativity of the ' ' operator. The ' ' operator is left-to-right associative, meaning it evaluates from left to right. This can lead to unexpected behavior if not taken into account.
In the second example, the expression can be parenthesized as:
<code class="cpp">const string message = ("Hello" + ",world") + exclam;</code>
As you can see, the two string literals, "Hello" and ",world," are concatenated first. This results in a string literal, which cannot be further concatenated with the string object "exclam."
There are several ways to resolve this issue:
<code class="cpp">const string message = string("Hello") + ",world" + exclam;</code>
<code class="cpp">const string message = "Hello" + (",world" + exclam);</code>
The ' ' operator is designed to concatenate string objects, not string literals. A string literal is an array of characters, and when used in an expression, it is converted to a pointer to its initial element. Adding two pointers, as in the case of concatenating string literals, is not allowed in C .
While you cannot concatenate string literals using the ' ' operator, you can combine them by placing them side-by-side:
<code class="cpp">"Hello" ",world"</code>
This is equivalent to:
<code class="cpp">"Hello,world"</code>
This is useful for breaking up long string literals onto multiple lines.
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