How to Handle Multiple Request Parts in Go (PDF and JSON)?

Parsing File and JSON Data Simultaneously from an HTTP Request with Go

In this scenario, you aim to parse both a PDF document and JSON data from a multipart HTTP request form. The complication arises from the requirement to handle two distinct parts within a single request.

To efficiently handle this situation, consider utilizing Go's http.(*Request).MultipartReader() method. This method returns a mime/multipart.Reader object, which allows you to iterate over individual parts of the request using the r.NextPart() function.

Revising your handler function to incorporate this method would look something like this:

<code class="go">func (s *Server) PostFileHandler(w http.ResponseWriter, r *http.Request) {
    mr, err := r.MultipartReader()
    if err != nil {
        http.Error(w, err.Error(), http.StatusInternalServerError)
        return
    }

    doc := Doc{}
    for {
        part, err := mr.NextPart()

        // This is OK, no more parts
        if err == io.EOF {
            break
        }

        // Some error
        if err != nil {
            http.Error(w, err.Error(), http.StatusInternalServerError)
            return
        }

        // PDF 'file' part
        if part.FormName() == "file" {
            doc.Url = part.FileName()
            fmt.Println("URL:", part.FileName())
            outfile, err := os.Create("./docs/" + part.FileName())
            if err != nil {
                http.Error(w, err.Error(), http.StatusInternalServerError)
                return
            }
            defer outfile.Close()

            _, err = io.Copy(outfile, part)
            if err != nil {
                http.Error(w, err.Error(), http.StatusInternalServerError)
                return
            }
        }

        // JSON 'doc' part
        if part.FormName() == "doc" {
            jsonDecoder := json.NewDecoder(part)
            err = jsonDecoder.Decode(&doc)
            if err != nil {
                http.Error(w, err.Error(), http.StatusInternalServerError)
                return
            }</code>

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