Home > Backend Development > C++ > Here are a few title options, keeping in mind the question format and focusing on the core issue: **Option 1 (Direct and Problem-Focused):** * **Why Does a Range-Based For-Loop Fail on Arrays Passed

Here are a few title options, keeping in mind the question format and focusing on the core issue: **Option 1 (Direct and Problem-Focused):** * **Why Does a Range-Based For-Loop Fail on Arrays Passed

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Release: 2024-10-25 01:36:30
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Here are a few title options, keeping in mind the question format and focusing on the core issue:

**Option 1 (Direct and Problem-Focused):**

* **Why Does a Range-Based For-Loop Fail on Arrays Passed to Non-Main Functions?**

**Option 2 (More Specific to

Range-Based For-Loop on Array Passed to Non-Main Function

When attempting to use a range-based for-loop on an array passed as an argument to a non-main function, you may encounter compilation errors. This is because array references decay to pointers, losing information about the array's size.

To address this issue, there are two approaches:

Using an Array Reference

You can pass the array as a reference to preserve its size information. This approach requires modifying the function signature, as shown below:

<code class="cpp">void foo(int (&amp;bar)[3]);</code>
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Using a Generic Template Function

For generic code that can handle arrays of varying sizes, you can define a template function that takes an array reference of any size:

<code class="cpp">template <std::size_t array_size>
void foo(int (&amp;bar)[array_size]) {
  // Range-based for-loop is valid now
}</code>
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