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How to Match Nested Brackets Without Recursion or Balancing Groups?

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Release: 2024-10-25 02:35:02
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How to Match Nested Brackets Without Recursion or Balancing Groups?

Matching Nested Brackets Without Recursion or Balancing Groups

Challenge:

Match a set of arbitrarily nested brackets using a regex flavor that lacks recursion and balancing group support, such as Java's java.util.regex, capturing three outer groups within the given string:

(F(i(r(s)t))) ((S)(e)((c)(o))(n)d) (((((((Third)))))))
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Solution: Forward References to the Rescue

Contrary to common belief, matching nested brackets without these advanced features is possible using forward references:

(?=\()(?:(?=.*?\((?!.*?)(.*\)(?!.*).*))(?=.*?\)(?!.*?)(.*)).)+?.*?(?=)[^(]*(?=$)
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Break it Down:

This complex regex operates in two stages:

  • Stage 1: Lookaheads identify sequences of balanced parentheses without consuming characters. This process continues until a complete outer group is found.
  • Stage 2: A capturing group extracts the contents of the matched outer group.

How it Works:

  • Checking for '(': Advance through the string until a '(' is encountered.
  • Matching Balanced Parentheses: Use two lookaheads to ensure the next '(' and ')' are matched in a balanced way, capturing the inner content.
  • Closing Bracket Check: Check for a closing ')' that matches the previously matched '(' and advance further.
  • End-of-Outer-Group Check: Ensure that no more '(' appear before the closing ')' of the outer group.

Inner Group Matching Variant:

For matching inner groups, the strategy remains the same, but a capturing group is used to save the matched content within a balanced pair of parentheses:

(?=\()(?=((?:(?=.*?\((?!.*?)(.*\)(?!.*).*))(?=.*?\)(?!.*?)(.*)).)+?.*?(?=)[^(]*(?=$))) 
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Comprehensive Breakage:

A table summarizes the components and functionality of the regex:

Note Component Description
(?=() Look for '('
(?: Start group for iteration
(?=.?((?!.?1)) Look for '(' not followed by 1, which contains the matched inner content
(.)(?!.2).*)) Capture inner content and check for at least one more ')'
(?=.?)(?!.?3)) Look for ')' not followed by 2, which contains the matched outer content
(. ) Capture outer content
. Consume a character
) Close group
? Match as few times as possible
.*?(?=1) Match up to and including the last '('
1*(?=2$) Match up to the last ')' without encountering more '('

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