Why Does My C Celsius to Fahrenheit Conversion Always Output 0?

Incorrect Conversion from Celsius to Fahrenheit

In C , converting from Celsius to Fahrenheit using floating-point arithmetic requires special attention. Consider the following code:

<code class="cpp">#include <iostream>

using namespace std;

int main() {
    float celsius;
    float fahrenheit;

    cout << "Enter Celsius temperature: ";
    cin >> celsius;
    fahrenheit = (5/9) * (celsius + 32);
    cout << "Fahrenheit = " << fahrenheit << endl;

    return 0;
}</code>

Why does this program output 0 for any Celsius input?

The issue lies in the integer division of (5/9). By default, C performs integer division, which results in 0 in this case. To address this, we must cast one of the operands to a floating-point type to force floating-point division. The corrected code below:

<code class="cpp">#include <iostream>

using namespace std;

int main() {
    float celsius;
    float fahrenheit;

    cout << "Enter Celsius temperature: ";
    cin >> celsius;
    fahrenheit = (5.0/9) * (celsius + 32);
    cout << "Fahrenheit = " << fahrenheit << endl;

    return 0;
}</code>

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