Disambiguation of Class Member in Multiple Inheritance with Overlapping Sets
In C , multiple inheritance with overlapping sets of types can lead to ambiguity when calling member functions with template parameters. To understand why, let's examine a base class template:
<code class="cpp">template <typename ... Types> class Base { public: template <typename T> typename std::enable_if<Contains<T, Types ...>::value>::type foo() { std::cout << "Base::foo()\n"; } };
The foo() member can only be called when the specified template parameter is present in the template parameter list of Base. Now, suppose we define a derived class Derived that inherits from multiple instances of Base with non-overlapping sets of types:
<code class="cpp">struct Derived: public Base<int, char>, public Base<double, void> {};</code>
When calling Derived().foo
Possible Solutions
<code class="cpp">template <typename... Bases> struct BaseCollector; template <typename Base> struct BaseCollector<Base> : Base { using Base::foo; }; template <typename Base, typename... Bases> struct BaseCollector<Base, Bases...>: Base, BaseCollector<Bases...> { using Base::foo; using BaseCollector<Bases...>::foo; }; struct Derived: public BaseCollector<Base<int, char>, Base<double, void>> {};</code>
This approach allows the derived class to access the correct base class implementation without any need for explicit using declarations or base class specification.
Understanding the ambiguity and implementing effective solutions in multiple inheritance with overlapping sets helps ensure clear and correct code execution.
The above is the detailed content of ## How to Disambiguate Class Member Calls in Multiple Inheritance with Overlapping Type Sets?. For more information, please follow other related articles on the PHP Chinese website!